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Aneli [31]
3 years ago
15

( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 = Simplify the exponential expression

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

2

Step-by-step explanation:

\frac{(3*2)^4*3^{-3}}{2^3*3}

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4  * 2^4

\frac{3^4*2^4*3^{-3}}{2^3*3}

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1  are same

\frac{3^1*2^4}{2^3*3^1}

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2



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9) What 2 numbers have a total of 28 and a difference of 6?<br>​
Vedmedyk [2.9K]

Answer:

Sum: 17 + 11 = 28

Difference: 17 - 11 = 6

Step-by-step explanation:

The sum of x and y is 28. In other words, x plus y equals 28 and can be written as equation A:

x + y = 28

The difference between x and y is 6. In other words, x minus y equals 6 and can be written as equation B:

x - y = 6

Now solve equation B for x to get the revised equation B:

x - y = 6

x = 6 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 28

6 + y + y = 28

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Now we know y is 11. Which means that we can substitute y for 11 in equation A and solve for x:

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Sum: 17 + 11 = 28

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