Answer:
Error of Andrew: Made incorrect factors from the roots
Step-by-step explanation:
Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is a factor of P(x). According to this definition:
(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.
Simplifying the brackets, we get:
(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.
This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a) which resulted in the wrong answer.
So, the polynomial would be:

Haha, part of my final today was about this! Don't worry, I got you!
y=2/3x-4
(the 2/3 is supposed to be a fraction)
F(b)=7b+8
you just need to change the x variable. make y into f(x) or in this case f(b)
1/2r -3= 3 (4-3/2r) is to be solved for r.
I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.
Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .
Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:
r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r
Now expand the right side, using the distributive property of
r - 3 = 24 - 9r
Regrouping so as to combine like terms:
10r = 30
Solving for r: r = 30/10 = 3
The value of r that satisfies this equation is 3