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kirill115 [55]
2 years ago
8

Can y’all help me with this ASAP please?

Mathematics
1 answer:
ladessa [460]2 years ago
5 0

Answer:

x + 3

5

Explanation:

x+3 is the equation for the first line to the left, and f(x)=5 is the second equation for the second line at the top.

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1000000100 hope it helps

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I need help on this question
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3 0
3 years ago
To rationalize the denominator of 2/square 13+ squared 11 , you should multiply the expression by which fraction?
eimsori [14]

<u><em>Answer:</em></u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}

<u><em>Explanation:</em></u>

To rationalize any expression, you must multiply it by its conjugate. A conjugate is defined as a similar expression to the original one but with an opposite sign

<u>This means that:</u>

The conjugate of a + b would be a -  b

Now, the given expression is \frac{2}{\sqrt{13}+\sqrt{11}}

<u>Consider the denominator:</u>

From the above, we can conclude that the conjugate of \sqrt{13}+\sqrt{11} is \sqrt{13}-\sqrt{11}

<u>And, remember that</u> we need to keep the value of the expression unchanged. This means that we must multiply both the numerator and the denominator by the same value

<u>Therefore:</u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}} in order to rationalize the denominator

Hope this helps :)

5 0
3 years ago
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Point N ( , 2 9) is on RS. A translation moves point N to its image, N'(6 3 , ). What is the distance, in units, between any poi
KatRina [158]
Hello!

Distance between two points (2,9) and (6,3) - 

<span>1. Take the Absolute Difference between the X points 2 and 6. The Absolute Difference is 4. </span>
<span>2. Square 4 = 16 </span>
<span>3. Take the Absolute Difference between the Y points 9 and 3. The absolute Difference is 12. </span>
<span>4. Square 12 = 144 </span>
<span>5 Add 144 + 16 = 160 </span>
<span>6. Take the Square root of 160 </span>

<span>12.6491106407

Hope this Helps at least! :)</span>
7 0
3 years ago
When you would not need to use the quadratic formula
sergiy2304 [10]

Answer: When the quadratic equation  can be factored or solved by completing the square, you do not need to use the quadratic formula

Step-by-step explanation: In the form   ax² + bx + c

Whenever <em><u>a</u></em> is 1 (implied, no coefficient of x²) and the constant,  <u><em>c</em></u>, is a multiple of numbers whose sum or difference is equal to <u><em>b</em></u>, factoring is much quicker and easier than using the quadratic formula.

Even when there is a coefficient of x², there are procedures to find the factors and solve for x without resorting to the quadratic formula.

3 0
3 years ago
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