I assume you mean, that an angle and two sides are known.
A formula that can be used for irregular triangles is the cosine rule.

'b' and 'c' must be sides that are beside the angle 'A' (angle opposite 'a').
Answer:1672
Step-by-step explanation:add 3% from each previous year to get to the 6th year
Using Sin^2 and Cos^2 identities,
= Cos^2(2A) + 4[(1/2)(1-Cos(2A)][(1/2)(1+Cos(2A)] = 1
= Cos^2(2A) + 1 -Cos^2(2A) = 1
0 = 0
There is nothing to solve for as it is an identity of sorts.
Answer:
2/3
Step-by-step explanation:
Y=-3 would be the correct answer:)