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2 years ago

I NEED HELP!! PLEASE ANSWER WITHIN NEXT 5 minutes PLEASE HELP!!!!! WHAT IS THE RULE????

Mathematics

1 answer:

Wewaii [24]2 years ago

6 0

Answer:

ΔEDC CNBD

Step-by-step explanation:

The triangles show AAA, which cannot be used to demonstrate congruency

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Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

2 years ago

I'm really stuck can someone help?

serious [3.7K]

You got it right the yellow highlighted

7 0

1 year ago

I need help wt this pls do it asap

viktelen [127]

Answer:

7/4

Step-by-step explanation:

its d because 4/7 =7/4

6 0

2 years ago

Sue’s height is 3 inches less than Ed’s height. Ed is 56 inches tall. How tall is Sue? Write an equation to represent the situat

belka [17]

Answer:

S = E - 3

Sue is 53 inches tall.

Step-by-step explanation:

Let Sue's age be represented by S and Ed's by E

Equation:

S = E - 3

E = 56 inches

S = 56 - 3 = 53 inches

5 0

2 years ago

GI = 6, HI = 8, DT = 12, what is IE?<br>a.12<br>b.16<br>c.8<br>d.4

harina [27]

Answer:

Option D

Step-by-step explanation:

By the property of intersecting chords,

If two chords are intersecting at a point inside a circle, product of lengths of the line segments on each chord is equal.

DI × EI = HI × GI

12 × EI = 8 × 6

EI = $\frac{48}{12}$

EI = 4

Therefore, Option D is the correct option.

5 0

2 years ago