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3 years ago

11

Determine whether the polygons are similar. If so, identify the correct similarity ratio and the similarity statement. PLEASE HE

LP!!!

2 answers:

enyata [817]3 years ago

7 0

The polygons are not similar :)

Blizzard [7]3 years ago

4 0

Answer:

No, the polygons are not similar

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FromTheMoon [43]

Answer:

5.6 days

Step-by-step explanation:

We are given;

Initial Mass; N_o = 25 g

Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)

k = 0.1229

Formula is given as;

N_t = N_o•e^(-kt)

Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

e^(-0.1229t) = 12.5/25

e^(-0.1229t) = 0.5

(-0.1229t) = In 0.5

-0.1229t = -0.6931

t = -0.6931/-0.1229

t = 5.6 days

4 0

3 years ago

What is the unit price if you divide 5.36 by 20 oz?

Alisiya [41]

Answer:

$0.27 per oz

I hope this helps :)

5 0

3 years ago

Can someone help me out please

AveGali [126]

Answer:

d

Step-by-step explanation:

bc it is equal on both sides

5 0

3 years ago

Read 2 more answers

The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?

Nastasia [14]

Y - 3 = 5(x - 4)
y - 3 = 5x - 20
y = 5x - 20 + 3 = 5x - 17
=> slope = 5

For perpendicular line, m2 = -1/m1 = -1/5

5 0

3 years ago

Read 2 more answers

Could someone explain this to me?

Ilya [14]

This is a simple differentiation problem. Let's start by taking the derivative of both sides (with respect to x):
$5y^4\frac{dy}{dx}+6y^2x+6x^2y\frac{dy}{dx}+20x^3 = 0$

Simplify:
$\frac{dy}{dx} (5y^4+6x^2y) + 6y^2x+20x^3 = 0$

Solve for dy/dx:
$\frac{dy}{dx} = \frac{-6y^2x-20x^3}{5y^4+6x^2y}$

Now, plug in the given points:
$\frac{dy}{dx} = \frac{-6(2)^2(-1)-20(-1)^3}{5(2)^4+6(-1)^2(2)} = \frac{24+20}{80+12}$

Further simplification gives:
$\frac{dy}{dx}|_{(2,-1)} =\frac{44}{92} = \frac{11}{23}$

So, your answer is 11/23 or B.

7 0

4 years ago