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motikmotik
3 years ago
12

Put -2, 33, -33, -100, -101, -99, 0, -1, 1, 100, 99 and 25 in order from greatest to least.

Mathematics
1 answer:
gregori [183]3 years ago
3 0

101, 100, 99, 33, 25, 2, 1, 0

You put the same numbers by accident

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Step-by-step explanation:


5 0
3 years ago
Let x represent the amount of frozen yogurt (in hundreds of gallons) sold by the G&T restaurant on any day during the summer
musickatia [10]

Answer:

a) The probability of selling less than 100 gallons (x≤1) is P=0.16.

b) The mean number of gallons is M=80 gallons.

Step-by-step explanation:

The probability of selling x, in hundred of gallons, on any day during the summer is y(x)=0.32x, in a range for x from [0;2.5].

The probability of selling less than 100 gallons (x≤1) is then:

P(x\leq1)=\int_0^{100}0.32x\cdot dx\\\\P(x\leq1)=0.16(x_b^2-x_a^2)\\\\P(x\leq1)=0.16(1^2-0^2)=0.16

The mean number of gallons can be calculated as:

M=\int_0^{2.5}(y(x)/x)\cdot dx=\int_0^{2.5}(0.32)\cdot dx\\\\M=0.32(x_b-x_a)=0.32(2.5-0)=0.32*2.5=0.8

3 0
3 years ago
Select the equivalent expression.
Free_Kalibri [48]

Answer:

\frac{7^{15}}{3^{30}}

Step-by-step explanation:

The given expression is:

(\frac{3^{-6}}{7^{-3}})^{5}

Moving the expression to the other side in the fraction changes its sign to opposite. A numerator with negative exponent, when written in denominator will have the positive exponent. Using this rule, we can write:

(\frac{3^{-6}}{7^{-3}})^{5}\\\\ = (\frac{7^{3}}{3^{6}} )^{5}

The exponent 5 can be distributed to both numerator and denominator as shown:

(\frac{7^{3}}{3^{6}} )^{5}\\\\ = \frac{(7^{3})^{5}}{(3^{6})^{5}}

The power of a power can be written as a product. i.e.

\frac{(7^{3})^{5}}{(3^{6})^{5}}\\\\ =\frac{7^{15}}{3^{30}}

So, the expression similar to the given expression and with positive exponents is: \frac{7^{15}}{3^{30}}

6 0
3 years ago
Read 2 more answers
I kinda need help with this
andreev551 [17]

Answer:

x = 1

Step-by-step explanation:

f(x) = 3 or y = 3

Locate y = 3 on the y- axis , go horizontally across to meet the line at (1, 3 )

Then

When f(x) = 3 , x = 1

7 0
3 years ago
How do you solve...3c^3d/9cd^-1
Maksim231197 [3]
<u>  3c³d  </u>  = <u>c²d²</u>
9cd^-1      3
4 0
4 years ago
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