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il63 [147K]
3 years ago
5

Find the value of x by filling in the blanks in the provided statement-reason solution.

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0

Answer:

m∠A +m∠B +m∠C = (sum of angles in a triangle △)

Marina CMI [18]3 years ago
6 0

Answer:1.) m∠A +m∠B +m∠C = (sum of angles in a triangle △)

2.) 24° + x + m∠C = 180°

3.) x = 156° - m∠C

Step-by-step explanation:

1. m∠A +m∠B +m∠C = (sum of angles in a triangle △)

2. 28°+x−4° + ______ = 180°

24° + x + m∠C = 180°

3) x = 180° - 24° - m∠C

x = 156° - m∠C

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3 years ago
Parallel to y=−3x−2, through (-3, -3)
VashaNatasha [74]

Answer:

Use the formula y-y1=m(x-x1) <---memorize this. The m here is the slope.

Step-by-step explanation:

The equation is in y=mx+b form

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The question wants you to find the equation that is Parallel to y=-3x-2 and passes through (-3,-3)=(x1,y1)

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So now all that's left is to plug into the equation.

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3 0
1 year ago
Choose one of the factors of 500x3 + 108y18
sammy [17]

Answer:

Option C

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).

Step-by-step explanation:

Given: 500x^3 +108y^\left (18\right )

the common factor from 500x^3 and 108y^\left (18\right ) is 4.

therefore, 4\cdot \left ( 125x^3+27y^\left (18\right ) \right )

4\cdot \left ( (5x)^3+(3y^6)^3 \right))

Now, use the formula for above expression: (a^3+b^3)=(a+b)(a^2-ab+b^2)

here, a=5x and b=3y^6

( (5x)^3+(3y^6)^3 \right))=(5x+3y^6)(25x^2-15xy^6+9y^12)

Therefore, we have

500x^3 +108y^\left (18\right )=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right )  \right )

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).








7 0
3 years ago
Read 2 more answers
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