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il63 [147K]
2 years ago
5

Find the value of x by filling in the blanks in the provided statement-reason solution.

Mathematics
2 answers:
Keith_Richards [23]2 years ago
7 0

Answer:

m∠A +m∠B +m∠C = (sum of angles in a triangle △)

Marina CMI [18]2 years ago
6 0

Answer:1.) m∠A +m∠B +m∠C = (sum of angles in a triangle △)

2.) 24° + x + m∠C = 180°

3.) x = 156° - m∠C

Step-by-step explanation:

1. m∠A +m∠B +m∠C = (sum of angles in a triangle △)

2. 28°+x−4° + ______ = 180°

24° + x + m∠C = 180°

3) x = 180° - 24° - m∠C

x = 156° - m∠C

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-4/9 + (-1/3) ? Helppppp
Alex

Answer:

- 7/9

Step-by-step explanation:

-4/9 + (-1/3)

= -(4/9) - (1/3)

= - (4/9 + 1/3)

= - (4/9 + 3/9)

= - [(4 + 3) / 9 ]

= - 7/9

5 0
2 years ago
In terms of the number of moose, what is the relative frequency of male moose, female moose, adult moose, and baby moose? Write
user100 [1]

Answer:

I'm sorry is there a chart/graph, etc. to give us more information?

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3 years ago
Read 2 more answers
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. W
Travka [436]

Complete question:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. Which equation explains the relationship between segment AB and segment A double prime B double prime?

A) segment a double prime b double prime = segment ab over 2

B) segment ab = segment a double prime b double prime over 2

C) segment ab over segment a double prime b double prime = one half

D) segment a double prime b double prime over segment ab = 2

Answer:

A) segment a double prime b double prime = segment ab over 2.

It can be rewritten as:

A"B" = \frac{AB}{2}

Step-by-step explanation:

Here, we are given triangle A″B″C which was formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin.

We know segment A"B" equals segment AB multiplied by the scale factor.

A"B" = AB * s.f.

Since we are given a scale factor of ½

Therefore,

A"B" = AB * \frac{1}{2}

A"B" = \frac{AB}{2}

The equation that explains the relationship between segment AB and segment A"B" is

A"B" = \frac{AB}{2}

Option A is correct

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The vertices of quadrilateral EFGH are listed below.
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