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3 years ago

The value of seven in 17.92 is what times as much as the value of seven in 92.17

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Answer:

100

Step-by-step explanation:

In 17.92, the 7 is in the ones digit, so its value is 7.

In 92.17, the 7 is in the hundredth digit, so its value is 0.07

7 is 100 times 0.07

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Assume that you have a binomial experiment with p = 0.5 and a sample size of 100.

Shalnov [3]

Answer:

Option D) 50

Step-by-step explanation:

We are given the following information in the question:

p = 0.5

Sample size,n = 100

We have to find the expected value of the distribution.

Formula:

$E(X) = np$

Putting the values, we get,

$E(X) = 100\times 0.5 = 50$

The expected value of this distribution is 50.

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4 years ago

F(x) = x3 – 3x2 - x + 3 what is the domain and range?

spin [16.1K]

Answer:

Domain: (-∞,∞)

Range: (-∞,∞)

Hope this helps.

6 0

3 years ago

Captain Umaima has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Nadia and her merciless band of thiev

brilliants [131]

Answer:

$\frac{9}{35}$ .

Step-by-step explanation:

We have been given that captain Umaima has probability 3/7 of hitting the pirate ship.

The pirate only has one good eye, so she hits the Captain's ship with probability 2/5.

The probability that pirate misses the captain's ship will be:

$\text{Probability that pirate misses captain's ship}=\text{1-probability that pirate hits captain's ship}$

$\text{Probability that pirate misses captain's ship}=1-\frac{2}{5}$

$\text{Probability that pirate misses captain's ship}=\frac{5}{5}-\frac{2}{5}$

$\text{Probability that pirate misses captain's ship}=\frac{5-2}{5}$

$\text{Probability that pirate misses captain's ship}=\frac{3}{5}$

So the probability that pirate misses captain's ship will be 3/5.

Since both events are independent, so by the multiplication rule of probability we will get,

$\text{Probability that captain hits the pirate ship, but pirate misses captain's ship}=\frac{3}{7}\times \frac{3}{5}$

$\text{Probability that captain hits the pirate ship, but pirate misses captain's ship}=\frac{3*3}{7*5}$

$\text{Probability that captain hits the pirate ship, but pirate misses captain's ship}=\frac{9}{35}$

Therefore, the probability that the Captain hits the pirate ship, but the pirate misses will be $\frac{9}{35}$ .

3 0

4 years ago

64° (3x + 1)º Find the value of x. I need help!! A 21 B 27 C 51 D 14

juin [17]

Answer:

Take away 1 from either side so the equation becomes 63=3x then divide both sides by 3 so it becomes 21=x which is your answer (option A)

Step-by-step explanation:

6 0

3 years ago

Please help me!

soldi70 [24.7K]

Answer:

-1.20

Step-by-step explanation:

You are correct because you just had to subtract 2.50 - 3.75 and you get -1.20.

6 0

3 years ago

Read 2 more answers