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Brilliant_brown [7]
3 years ago
14

Someone please let me know the answer ​

Mathematics
1 answer:
erastova [34]3 years ago
3 0

Answer:

The answer is 30°

Step-by-step explanation:

when \:  \:   \sqrt{3}  \sin( \alpha )  -  \cos( \alpha )  = 0 \\  \sqrt{3}   \sin( \alpha )  =  \cos( \alpha )  \\ multiply \: by \:  \frac{1}{ \sqrt{3}  \cos( \alpha ) }  \\ then \\  \frac{ \sin( \alpha ) }{ \cos( \alpha ) }  =  \frac{1}{ \sqrt{3} }  \\  \tan( \alpha )  =  \frac{1}{ \sqrt{3} }  \\ then \:  \alpha  = 30

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iren2701 [21]

Answer: The data is a random sample from the population of interest.

And

Individual observations can be considered independent.

Step-by-step explanation:

On khan academy

4 0
3 years ago
Simplify radicals problems attached please help!
Finger [1]

Answer:

  G7.  (2√3)/3

  G8.  -2+√7

  G9.  (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}

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G8.

\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2

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G9.

\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}

_____

<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0
3 years ago
Help!! working with area
Artyom0805 [142]
The area of the figure is 360 square yards
5 0
3 years ago
The diagram shows a sector of a circle radius 11 cm.
nadya68 [22]

Answer:

Perimeter of sector is 47.93 cm which is greater than 47.5 cm

Step-by-step explanation:

Mathematically, the perimeter of a sector is length of the arc plus 2 radii

The length of the arc is;

theta/360 * 2 * pi * r

where theta is the angle subtended by the arc at the center of the circle

Thus, we have

135/360 * 2 * 22/7 * 11 = 25.93

Add 2 radii = 25.93 + 2(11) = 47.93 cm

This is greater than what we are asked to calculate and thus we have shown what we are asked to show

4 0
3 years ago
Jose found $2.25 in his pocket. He found q quarters on his walk to the park. choose the expression that shows how much money he
MAVERICK [17]
B because Q is how much he found and a quarter is 0.25 so it’s q0.25 and you add that to 2.25 that’s how much he had in his pocket
5 0
2 years ago
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