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cupoosta [38]
3 years ago
15

If I bought 3 shirts that cost the same and I got a coupon for 10 dollars off and I spent 65 altogether what equation can be use

d to find the cost of the shirt
Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0
I think this is the answer
65+10/3
Hope this helps
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Brian cut a piece of cardboard in the shape of a trapezoid the area of the cut out is 43.5 cm² if the bases are 6 cm And 8.5 cm
Likurg_2 [28]

Answer: the height of the trapezoid is 6 cm

Step-by-step explanation:

The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of The bases are the 2 sides of the trapezoid which are parallel with one another.

h represents the height of the trapezoid.

From the information given,

a = 6 cm

b = 8.5 cm

If the area of the cut out is 43.5 cm², then

53.5 = 1/2(6 + 8.5)h

Cross multiplying by 2, it becomes

43.5 × 2 = (6 + 8.5)h

87 = 14.5h

h = 87/14.5 = 6 cm

8 0
3 years ago
Kieran and Ariana are biking on a trail. Kieren begins 8 miles ahead of Ariana and bikes at an average speed of 4 miles per hour
Fittoniya [83]

I'm so sorry if this was confusing for you but just saying the answer clearly is (4,24)


3 0
3 years ago
Read 2 more answers
Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S
Sophie [7]

Answer:

Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that A=J^{-1}AJ. Thus, A↔A.

<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that A=P^{-1}BP. In this equality we can perform a right multiplication by P^{-1} and obtain AP^{-1} =P^{-1}B. Then, in the obtained equality we perform a left multiplication by P and get PAP^{-1} =B. If we write Q=P^{-1} and Q^{-1} = P we have B = Q^{-1}AQ. Thus, B↔A.

<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have A=P^{-1}BP and from B↔C we have B=Q^{-1}CQ. Now, if we substitute the last equality into the first one we get

A=P^{-1}Q^{-1}CQP = (P^{-1}Q^{-1})C(QP).

Recall that if P and Q are invertible, then QP is invertible and (QP)^{-1}=P^{-1}Q^{-1}. So, if we denote R=QP we obtained that

A=R^{-1}CR. Hence, A↔C.

Therefore, the relation is an <em>equivalence relation</em>.

4 0
3 years ago
Find the common difference of the arithmetic sequence - 11,-16, -21, ...<br> ?<br> Answer.
saveliy_v [14]

Answer:-26 is the next number

Step-by-step explanation:you just -5

6 0
2 years ago
A beam of polarized light with intensity I0 and polarization angle θ0 strikes a polarizer with transmission axis θTA. What angle
11Alexandr11 [23.1K]

Answer:

θ^{TA} - θ^{0}

Step-by-step explanation:

According to the theory of Malus, when a completely plane polarized light is incident on an analyzer, the intensity 'I' of the light wave transmitted by the analyzer is proportional to the square of the cosine of angle between the transmission axes of the polarizer and analyzer. Therefore:

Using the theory of Malus, we need to estimate the angle between the transmission axis θ^{TA} and the polarization axis θ^{0}.

Thus:

angle θ = θ^{TA} - θ^{0}

4 0
3 years ago
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