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anzhelika [568]
3 years ago
12

Evaluate 5^-4 A.1/625 B.-1/625 C.625 D.-625

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

A

Step-by-step explanation:

that's the right answer

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I know the answer but the calculator doesn't seem to give the right one
Diano4ka-milaya [45]

Answer:

Make sure the mode is on degree and not radian! Common mistake

6 0
3 years ago
The coldest day in ohio clocked in at 40 below zero. In one day though the temperature changed to 20 below zero How much tempera
Zolol [24]
40 below 0 would be -40 and 20 below 0 would be -20°. So there’s a change of (increase of) 20° that day. It would also make sense if you drew a number line. You would see the interval between -40 and -20 is 20.
6 0
3 years ago
Which equation finds the area of a square with a side length of 5n4 units?
AnnyKZ [126]

Answer:

25n^8

Step-by-step explanation:

Area of a square is length×length

Length=5n^4

Area=5n^4×5n^4

=(5×5)(n^4+4)

=(25)(n^8)

=25n^8

So the area of a square is 25n^8

6 0
3 years ago
Read 2 more answers
What is the value of a when we rewrite 8^x as a^-x/9​
Andre45 [30]

Answer:

a = \frac{1}{134217728}

Step-by-step explanation:

Given

8^x = a^{-x/9}

Required

Find a

Take log of both sides

log(8^x) = log(a^{-x/9})

Apply law of logarithm

x\ log(8)  = (-x/9) log(a)

Divide both sides by a

log(8)  = -\frac{1}{9} log(a)

Multiply both sides by -9

-9\ log(8)  = log(a)

Apply law of logarithm

log(8^{-9})  = log(a)

Cancel out log

8^{-9}  = a

Rewrite as:

a = 8^{-9}

Apply law of indices

a = \frac{1}{8^9}

a = \frac{1}{134217728}

4 0
3 years ago
Juan wants to change the shape of his vegetable garden from a square to a rectangle, but keep the same area so he can grow the s
sergeinik [125]

The quadratic equation that would model this scenario is

x^{2} = 2x(x-16)

Let us take the side of the square = x

Area of the square = x²

Length of the rectangular garden = 2x

Width of the rectangular garden = x-16

So, the area of the new vegetable garden = length*width

Area of the new or rectangular vegetable garden = 2x(x-16)

<h3>What is a quadratic equation?</h3>

The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by ax^2+bx+ccoefficient x^{2}non-zero.

Since it is given that

Area of square garden = area of the rectangular garden

x^{2} = 2x(x-16)

Thus, the quadratic equation that would model this scenario is

x^{2} = 2x(x-16)

To get more about quadratic equations refer to:

brainly.com/question/1214333

5 0
2 years ago
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