Solve <br>(3431)−2/3÷(491)3/2 <br><br>a. 16807<br>b.343<br>c.49<br>d.2401

Mei likes to make desserts for bake sales. Last month, she made 2 batches of brownies and 3 batches of cookies, which called for

tino4ka555 [31]

Answer: she uses 2 eggs for one batch of brownies and 4 eggs for one batch of cookies.

Step-by-step explanation:

Let x represent the number of eggs that she uses for one batch of brownies.

Let y represent the number of eggs that she uses for one batch of cookies.

Last month, she made 2 batches of brownies and 3 batches of cookies. This means that

2x + 3y = 16 - - - - - - - - - -1

The month before, she baked 1 batch of brownies and 1 batch of cookies, which required a total of 6 eggs. This means that

x + y = 6 - - - - - - - - - - - - - 2

Multiplying equation 1 by 1 and equation 2 by 2, it becomes

2x + 3y = 16

2x + 2y = 12

Subtracting, it becomes

y = 4

Substituting y = 4 into equation 2, it becomes

x + 4 = 6

x = 6 - 4 = 2

7 0

4 years ago

The volume V of a right‑circular cylinder is computed using the values d = 3.1 m for the diameter and h = 6.6 m for the height.

pantera1 [17]

Answer:

6%

Step-by-step explanation:

A function f(x) can by approximated at and around a point, say x = a by,

f(x) = f(a) + f'(a)(x-a)

where, $f'(x)=\frac{df}{dx}$

Here, volume V is a function of radius r and height h. In the 2 dimensional case, we have to take the partial derivatives.

Given,

$V=\pi r^2h$

or, $dV=\frac{\partial V }{\partial r}dr+ \frac{\partial V }{\partial h}dh$

at r = 1.55 m and h = 6.6 m

$dr=0.02\times1.55m=0.031m$

$dh=0.02\times6.6m=0.132m$

$\frac{\partial V }{\partial r}=2\pi r h=2\pi \times 1.55\times 6.6=64.277$

$\frac{\partial V }{\partial h}=\pi r^2=7.5477$

Therefore, $dV=(64.277\times.031)+(7.5477\times0.132)=2.9889m$

Also, $V=\pi r^2h=49.8147m$

Hence, maximum error is given by,

$R=\frac{2.9889}{49.8147} \times 100$

= 6%

7 0

4 years ago

(15 points) Complete the inequality. (-1/9)(3/5) __ - 2/15

mario62 [17]

Step-by-step explanation:

-1/9 × 3/5 = -1/15

-1/15>-2/15

3 0

3 years ago

Read 2 more answers

Select the correct texts in the table.

ra1l [238]

Based on the given texts in the table about the graph of the function, the true statements are:

The graph crosses the y-axis at (0,-15).
The graph has a point of discontinuity at x = -2.
The graph is increasing over the interval (4, ∞o).
The domain of the function is all real numbers.

<h3>Which statements are true of the graph of the function?</h3>

The function, 4x - 15 shows that 15 is the y-intercept which means that the graph will cross the y-axis at (0,15).

The point of discontinuity is x = - 2 and we see this with the gap created at x < -2 and -2 ≤ x ≤ 4.

The graph is indeed increasing over the interval (4, ∞o) because any value of x that is greater than 4 will increase f(x) = $3^x^-^4$ .

The domain of the function is also all real numbers as it begins at negative infinity and ends at infinity, (-∞, ∞).

Find out more on point of discontinuity at brainly.com/question/9553665.

#SPJ1

7 0

2 years ago

FIND THE INDICATED PROBABILITY FOR THE FOLLOWING:

luda_lava [24]

The value of the probability P(A) is 0.40

<h3>How to determine the probability?</h3>

The given parameters about the probability are

P(A or B) = 0.6

P(B) = 0.3

P(A and B) = 0.1

To calculate the probability P(A), we use the following formula

P(A and B) = P(A) + P(B) - P(A or B)

Substitute the known values in the above equation

0.1 = 0.3 + P(A) - 0.6

Collect the like terms

P(A)= 0.1 - 0.3 + 0.6

Evaluate the expression

P(A)= 0.4

Hence, the value of the probability P(A) is 0.40

Solve (3431​)−2/3÷(491​)3/2 a. 16807b.343c.49d.2401​

Solve (3431)−2/3÷(491)3/2 a. 16807b.343c.49d.2401