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Nadya [2.5K]
3 years ago
8

Describe the recursive formula ?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
4 0

Answer:

  • You have a linear function
evablogger [386]3 years ago
3 0

Answer:

Linear

Step-by-step explanation:

You might be interested in
What is a factor of 98
ziro4ka [17]

Answer: The factors of 98 are 1, 2, 7, 14, 49, 98


Step-by-step explanation:

1 x 98 = 98, 2 x 49 = 98, 7 x 14 = 98, 14 x 7 = 98, 49 x 2 = 98


Hope this helps fren <3

8 0
3 years ago
What percent of 9.4 cm is 3.5 cm?
tia_tia [17]
9.4 cm --- 100%
3.5 cm --- x%

x = 3.5/9.4 * 100 ≈ 37.2%
4 0
3 years ago
Read 2 more answers
Pls help this is major, ill mark u brainliest
Lera25 [3.4K]

Answer:

105

Step-by-step explanation:

A=lw   A=(.5)πr²

to get the area of the shaded parts you have to subtract the area of the semicircle from the area of the rectangle

A=(16)(9)

A=144

A=\frac{(3.14)(5)^2}{2} A=\frac{(3.14)(25)}{2} A=\frac{78.5}{2}

A=39.25

subtract the areas

144-39.25=104.75

104.75 ≅ 105

4 0
3 years ago
Find the value of x. Round your answer to the nearest tenth.
CaHeK987 [17]

Encuentra el valor de x. Redondea tu respuesta a la décima más cercana.

8 0
3 years ago
Verify the trig identity: tan^2 theta + cot^2 theta / csc^2 theta = sec^2 theta
Mars2501 [29]

Answer:

See proof below

Step-by-step explanation:

In trigonometry identity

tan^2 theta = sin^2 theta /cos^2 theta

cot^2 theta = cos^2 theta/sin^2 theta

csc^2 theta = 1/sin^2 theta

Substitute into the expression

(sin^2 theta /cos^2 theta )+ (cos^2 theta/sin^2 theta)/1/sin^2 theta

= [sin^4theta + cos^4theta/cos^2 theta sin^2 theta]÷(1/sin^2 theta)

= 1/cos^2 theta sin^2 theta÷(1/sin^2 theta)

= 1/cos^2 theta sin^2 theta * sin^2 theta/1

= 1/cos^2theta

= sec^2theta (Proved!)

3 0
3 years ago
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