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2 years ago

A miniature portrait of Frosty the Snowman is square and has an area of 100 square

Mathematics

1 answer:

saveliy_v [14]2 years ago

3 0

Answer:

25 centimeters

Step-by-step explanation:

Well a square has 4 sides, and 100 divided by 4 is 25.

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Suppose you know the perimeter of n octagons arranged as shown. What would you do to find the perimeter if 1 more octagon was ad

kogti [31]

As shown in the figures given :

For Figure 1 : perimeter = 8 units [As can be seen in the figure]

For figure 2(with 2 octagons) : perimeter = 8 × 2 - 1 = 15 units [since 1 side is common ]

For figure 2(with 3 octagons) : perimeter = 8 × 3 - 2 = 22 units [since 2 sides is common ]

If one more octagon is added

then perimeter = 8 × 4 - 3 = 29 units [since 3 sides will be common ]

3 0

3 years ago

Enter the rate of change of the table below

poizon [28]

The rate of change is 23

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2 years ago

I need help with these plzz

dimaraw [331]

Uhh my brains hurts looking at that

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3 years ago

Read 2 more answers

Fredericka can make 65% of her shots from the free-throw line. if she shoots 75 times, how many shots can she expect to go in?

exis [7]

All we need to do is find 65% of 75
we need to know that 65% = 0.65
and we multiply 0.65 and 75
soooo
75 x 0.65 = 48.75
so she sould expect to make about 48 shots into the hoop
hope this helps:)
and dont forget 2
MARK ME BRAINLIEST! :D

5 0

3 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

2 years ago