The Winter Olympics are held every 4 years.
The final rotational speed ω_final and the instantaneous power P delivered to the wheel are; ω_f = √((ω_i)² + 2(FL/(kmr²) and P = Frω_i
<h3>What is the Instantaneous Power?</h3>
A) From rotational kinematics, the formula for the final angular velocity is;
ω_f = √((ω_i)² + 2αθ)
where;
α is angular acceleration
θ = L/r. Thus;
ω_f = √((ω_i)² + 2α(L/r))
Now, α = T/I
Where;
I is moment of inertia = k*m*r²
T is t o r q u e = F * r
Thus;
α = (F * r)/(kmr²)
α = F/(kmr)
ω_f = √((ω_i)² + 2(F/(kmr))(L/r))
ω_f = √((ω_i)² + 2(FL/(kmr²)
B) Formula for instantaneous power is;
P = Fv
where at t = 0; v = rω_i
Thus;
P = Frω_i
Read more about Instantaneous Power at; brainly.com/question/14244672
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Answer:
Angles are measure of rotation, along with its direction of rotation. The supplement angle of 77° is 103°
How to find the supplement angle of an angle?
Supplement angle of an angle is such that sum of both of them comes as 180°
Thus, if an angle is of A°, then its supplementary angle is 180° - A°
For the given case, we let the first angle be of A° = 77°, then its supplementary angle with measure B° is:
Thus, The supplement angle of 77° is 103°
