This is true. Exercise physiology, like biomechanics, is a subdiscipline in the biophysical sphere.
<h3>What is exercise physiology?</h3>
This is the term that is used to refer to the way that our body is known to respond to certain activities such as exercises.
The study is very important in order to know how the human body adapts to exercise. There are two types of exercise physiology. These are the sports and the clinical type.
The sports physiology is the one that is related to athletes. They are used to develop training regimen for the athletes after observing the way that their body would normally respond to exercises.
The three main types are aerobic, muscle strengthening, this would involve the activities that may include weight lifting and also the flexibility of humans.
Read more on exercise physiology here:
brainly.com/question/25732119
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This is the transitional word or phrase that most effectively introduces the evidence in the sentence:
For example,
<h3>What are transitional words?</h3>
Transitional words or phrases are indeed words or phrases that link one idea to the other. These type of words are very important because they give texts coherence and fluency.
In this exercise, "For example," is the transtitional phrase that allows you to continue with a specific explanation of the evidence in the text.
I was able to find the complete instructions for the exercise online and these were the other options:
- (As it is now)
- Earlier,
- Therefore,
- Elsewhere,
Check more information about transitional words here brainly.com/question/2372495
Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.
Explanation:
Let a Force pushes the hockey puck of mass m.
Then acceleration, a= \frac{F}{m}a=mF
From the equation of motion,
\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)
In the second case, when mass is 2m, then acceleration,
a'=\frac{F}{2m}a′=2mF
and t' is the time taken.
The final speed is v,
\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)
Hence, it would take two times the previous amount of time to push the pluck of double mass.
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Idrk but i do know that it is on answer.com