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katrin2010 [14]
3 years ago
5

1+1 hows your day been, don’t forget to take a break from school guys and chill, put on some music and have a drink!!!!!!!

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer: my day has been alright I have a lot of work and nobody is answering them or helping so I feel a bit frustrated and stressed... but thank you for caring <3

Step-by-step explanation:

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In a writing competition, the first place winner receives 1/2 of the prize money. The second runner up receives 1/4 of what the
worty [1.4K]

Answer:

10,000 is the total amount of.money that was distributed

6 0
2 years ago
The gross weight of a package and its contents is 11 pounds 5 ounces. If the packaging weighs 1 pound 15 ounces, what's the net
dsp73
Answer A
For ease convert both into ounces.

Gross = (11x16) + 5 = 181 ounces
Packaging = (1x16) + 15 = 31 oz.

Now subtract Packaging from Gross

181 - 31 = 150 oz.

Divide by 16 to get pounds

150/16 = 9.375 - hence 9 lb.

and multiply 16 by .375 for ounces

0.375 x 16 = 6 oz.

Thus A : 9lb 6 oz
5 0
3 years ago
Read 2 more answers
PLSSS HELP IF YOU TURLY KNOW THISS
Vladimir [108]

Answer:

B

Step-by-step explanation:

There is two wholes and one half.

6 0
2 years ago
A copy machine makes 171 coies in 4 minutes and 45 seconds. How many copies does it make per minute?​
Jobisdone [24]

Answer:

36

Step-by-step explanation:

171/(4+0.75) =36

you want it to be in minutes, so calculate the 45 seconds over 60 seconds, which is 0.75. Add that to the 4 minutes, and divide the total number of copies over the time used, and you have speed/minute.

3 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
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