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Pachacha [2.7K]
2 years ago
5

Please help me answer this.

Mathematics
1 answer:
inna [77]2 years ago
5 0

Answer:

D. 4,-1

Step-by-step explanation:

The mathmatical way to solev it is to find the linear equation and plug in the points, but i just looked at the graph to see which point was in the shaded region.

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Write the equation of a line through points (5, 5) and (1, 0) in point-slope form
klasskru [66]

Answer:

y=(5/4)x-5/4

Step-by-step explanation:

First we need to find the slope:

\frac{y_{2}-y_{1} }{x_{2}-x_{1} }

=\frac{5-0}{5-1}

=5/4

The SLops is 5/4

point-slope forum is

y=(5/4)x-5/4

(i think)

3 0
3 years ago
The Helheim glacier in Greenland enters the ocean in a 6.3 kilometer wide fjord. The terminus of the glacier retreated 7.5 kilom
vladimir1956 [14]

Answer:

7.56 km²

Step-by-step explanation:

Given data:

Width of the fjord, w = 6.3 km

Retreated terminus of the glacier between may 2001 and June 2005, d = 7.5 km

thus, the length lost , y = 7.5 - 6.3 = 1.2 km

now, the area is given as:

A = Length × width

on substituting the values, we get

A = 1.2 × 6.3

or

A = 7.56 km²

Hence, the surface area lost by the glacier in the fjord is 7.56 km²

7 0
3 years ago
One angle of an isosceles trapezoid has measure 57. What are the measures of the other angles?
Kobotan [32]
\alpha =57^o\\ \\ The \ interior \ angle \ at \ the \ shortest \ base \ is \ equal \ to :\\ \\ \beta = 180^o - 57^o = 123^o



3 0
3 years ago
Read 2 more answers
Esteban wants to take out a $5,000 loan from the bank and is offered two choices. If he pays the loan back within 3 years, he wi
castortr0y [4]

Answer:

ESTEBAN IS FOKING BROKE

Step-by-step explanation:

8 0
2 years ago
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work
valina [46]

Answer:

Step-by-step explanation:

Question

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.​

perimeter of a triangle = AB+AC+BC

Using the distance formula

AB = sqrt(-2-5)²+(2-2)²

AB = sqrt(-7)²

AB =sqrt(49)

AB =7

BC = sqrt(-2+2)²+(2-5)²

BC = sqrt(0+3²)

BC =sqrt(9)

BC =3

AC= sqrt(-2-5)²+(2-5)²

AC= sqrt(-7)²+3²

AC =sqrt(49+9)

AC =sqrt58

Perimeter = 10+sqrt58

5 0
2 years ago
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