Please help me answer this.

Daria's goal is to run 7 miles each weekend.she ran 3 and 1/3 mules on saturday and 3 and 3/4 on Sunday. by how much did she bea

oksano4ka [1.4K]

She beat her goal. her total was 7 miles and 1/12 as she ran .1 miles longer find the lcd of 4 and 3 wich is 12 and add the num. to get 13 and that simplifed is 1 1/12+6 which is 7.1 or
7 1/12 mules

5 0

2 years ago

Please help me please

erastovalidia [21]

-3,4 the reflection is just making it positive or negative in a different section in this case u change the y to a positive and put it on the second plain

Hope I helped plz giv brainlyest bro I need it

7 0

2 years ago

Two increased by the product of a number and 9 is greater than or equal to 25.

Marianna [84]

Answer:

x≥2.56

Step-by-step explanation:

first we can write the inequality

2+9x≥25

we can now solve this with algebra

9x≥23

x≥2.56

3 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

2 years ago

2

Mademuasel [1]

Answer:

I only

Step-by-step explanaition:

The domain (x) can not repeat in order for it to be a function.

3 0

2 years ago

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