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2 years ago

PLEASE HELP ANYONE HELP ?!!!!!!!!!!!!!!!)))):::::

Mathematics

2 answers:

stealth61 [152]2 years ago

3 0

Answer:

Step-by-step explanation:

givens: x=4

now try your options:

3(4)+3=15

12+3=15

15=15

The first option is correct, therefore the answer is 3x

GuDViN [60]2 years ago

3 0

Answer: I think it is 3x

Step-by-step explanation: I've done this before.

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What is a surface area of the cuboid with 4,5 and 9

Anettt [7]

Answer:

SA = 202

Step-by-step explanation:

Surface area = Sum of all 6 areas of each side of the cuboid

SA = 2 (4·5 + 5·9 +9·4), because there are 2 of each kind of sides

SA = 2 (20+ 45 + 36)

SA = 2·101

SA = 202

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1 year ago

In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AC=5 and BH=2, find AH and CH.

Yakvenalex [24]

Answer:

AH = 1 or 4

CH = 4 or 1

Step-by-step explanation:

An altitude divides a right triangle into similar triangles. That means the sides are in proportion, so ...

AH/BH = BH/CH

AH·CH = BH²

The problem statement tells us AH + CH = AC = 5, so we can write

AH·(5 -AH) = BH²

AH·(5 -AH) = 2² = 4

This gives us the quadratic ...

AH² -5AH +4 = 0 . . . . in standard form

(AH -4)(AH -1) = 0 . . . . factored

This equation has solutions AH = 1 or 4, the values of AH that make the factors be zero. Then CH = 5-AH = 4 or 1.

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2 years ago

6-1 reteach solving systems by graphing

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Find A, B, and C 7th Grade Math Please help me answer this

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Answer:

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2 years ago

(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$