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2 years ago

There are 60 students in a classroom, 50% of the students are

Mathematics

1 answer:

vivado [14]2 years ago

6 0

Answer:

Step-by-step explanation:

If 50% of students are boys that means there are 30 boys and 30 girls. Then if 30% of boys are 10 and 60% of girls are 18. You add 18+10 and that gives you 28.

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Finding area of shaded sectors.

tekilochka [14]

Answer:

69.81 sq. m. (rounded to 2 decimal places)

Step-by-step explanation:

The sector of a circle is "part" or "portion" of a circle. The formula for the area of a sector is:

$A=\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the central angle

r is the radius

Given the figure, the arc is given as 80 degrees, but not the central angle of the shaded sector. But from geometry we know that the central angle and the intercepted arc have the same measure. So we can say:

$\theta = 80$

Also, the radius of the circle shown is 10 meters, so

r = 10

Now, we substitute in formula and find our answer:

$A=\frac{\theta}{360}*\pi r^2\\A=\frac{80}{360}*\pi (10)^2\\A=\frac{2}{9}*100\pi\\A=\frac{200\pi}{9}\\A=69.81$

Thus,

The area of the shaded sector is 69.81 sq. meters.

5 0

2 years ago

Graph f(x)=2x+1 and g(x)=−x+7 on the same coordinate plane.

Tamiku [17]

Answer:

x = 2

Step-by-step explanation:

To solve the equation, you need to set both functions equal to each other and simplify to find the value of "x".

f(x) = 2x + 1

g(x) = -x + 7

f(x) = g(x) <----- Given equation

2x + 1 = -x + 7 <----- Insert functions

3x + 1 = 7 <----- Add "x" to both sides

3x = 6 <----- Subtract 1 from both sides

x = 2 <----- Divide both sides by 3

8 0

1 year ago

Triangle ABC has vertices A(-3,0) B(0,6) C(4,6). Find the equations of the three medians of triangle ABC

Mariana [72]

Answer:

1. $y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}$

2. $y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}$

Step-by-step explanation:

A(−3, 0), B(0, 6), and C(4, 6)

using the midpoint formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$ we can find all of their midpoint which is necessary to complete question 1 and 2

Mid AB=(-1.5, 3), Mid BC=(2, 6), Mid AC=(0.5,3)

Next, we have to find the slope of from the vertex and the midpoint of each side. We use the slope formula: $\frac{y_2-y_1}{x_2-x_1}$ .

You would get -6, 6/5, and 6/11.

Next you substitute in the coordinates for the equation of each for example: y=-6x, you switch in the set of cords AB which is (-1.5, 3). 3=-6(-1.5)+z and find that z=6, so the equation is y=-6x+6. As for the rest, repeat the same process until you find all 3 cords. You should get an answer of $y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}$

For question 2,

The line has to be perpendicular bisector to the midpoint, signifying that it has to split 2 angles into congruent angles and a side into half. In order to do that we need to first find the opposite reciprocal of each side's slope. Which means we need to once again use the slope formula and get the opposite reciprocal by $-\frac{1}{slope}$ . For all the opposite reciprocal slopes you get will be incorporated into the final formulas. That gives us the slopes of -1/2, 0 and -7/6. Then do the same process of matching cords with these incomplete equations and you can find the final equations of $y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}$

I hope that helped with your question!! :)

Also I'm an RSM student too and I didn't know how to do them before so I searched it up.

6 0

2 years ago

If f(x)=3x²-5x+4, then f(-2) =

igomit [66]

Answer:

Step-by-step explanation:

First let's re-write the equation:

f(x) = 3x² - 5x + 4

If f(-2). then we can re-write the equation as:

f(-2) = 3(-2)² - 5(-2) + 4

We must solve for exponent first: (-2)² = 4

f(-2) = 3(4) - 5(-2) + 4

Then solve for multiplication:

f(-2) = 12 + 10 + 4

Finally addition:

f(-2) = 26

that means that in a function, if X = -2, then F is equal to 26

4 0

1 year ago

You have a bag with 10 pennies, 10 quarters, and 10 dimes. You draw 2 coins without replacement. Which action, performed before

Nitella [24]

Answer:

Removing pennies and dimes from the bag

Step-by-step explanation:

From the beginning, we have a 1 in 3 chance of drawing a quarter. If we were to add dimes and/or pennies to the bag, this would make us more likely to draw a dime or a penny, and less likely to draw a quarter. Proportionally, we want the most quarters in the bag to get the highest probability of drawing a quarter from the bag.

8 0

2 years ago