Answer:
Step-by-step explanation:
(a) the co-ordinates of the point where the line crosses the y-axis,
y intercept occurs when x = 0
y = 5 - 2(0)
y = 5
(0, 5)
(b) the gradient of the line,
the general line formula is y = mx + b, where m is the slope and b is the y intercept.
y = 5 - 2x
y = -2x + 5
m = -2
(c) the equation of a line parallel to L.
Parallel lines have the same slope, but different y intercepts.
The simplest parallel line formula is
y = -2x + 0
y = -2x
Hello!
I believe that the answer would be 40²
I hope this helps!
Answer:
Luis:
Marina:
Answer: Marina got the better percent score than Luis
Marina:
Answer:
2/2 = 1
Step-by-step explanation:
y2 - y1 4 - 2 2 Equals 1
x2 - x1 8 - 6 2
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
