Evaluate int[sin^3(θ)cos(θ)dθ] with u = sin(θ)
du/dθ = cos(θ), dθ = du/cos(θ)
The integral becomes:
int[u^3•cos(θ)du/cos(θ)]
= int[u^3•du]
= u^4/4 + C
Substitute u = sin(θ) to get back a function of θ:
sin^4(θ)/4 + C
x
for the exponent, count how many tens like 10
for word write ten to the x power
If u mutipled 4x4 8 spit I t in half and then 4 x d xx then have your answer