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oksano4ka [1.4K]
3 years ago
13

Please answer the answer correctly

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

From (-3,0) to (3,2) the equation is y=1/3x + 1 and the other side from (3,1) to (4,-1) is y= -3x + 11

Step-by-step explanation:

Thanks for helping me with the other one

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1.221 x 1/100 =<br> answer with the product. Correct answer will be awarded with branliest
Vladimir79 [104]

Answer:

0.1221

Step-by-step explanation:

8 0
3 years ago
Your friend can clap his hands 28 times in 12 seconds. How many times can your friend clap his hands in 0.5 minute?
Mandarinka [93]

Answer:

6 times

Step-by-step explanation:

28claps =12seconds

? = 0.5minutes

60seconds=1minute

? =0.5 minutes

(cross multiply)

60*0.5/1 = ?

?=30seconds

28claps = 12secs

? =30secs

28*30/12 =?

?=70claps

4 0
3 years ago
A florist normally takes 20 hours to assemble 10 flower arrangements how long do it takes to do one flower arrangement
Mariana [72]
20/10= 2

All you need to do is divide the number of hours it takes by the number of flower arrangments. So, it takes the florist 2 hours to assemble one flower arrangement.

I hope this helps!
~kaikers
5 0
3 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
Solve and describe the graph of the inequality: j + 16 ≥ -21
liraira [26]

Answer:

j ≥ -37

Step-by-step explanation:

j + 16 ≥ -21

move constant to the right hand side and change its sign

j ≥ -21 - 16

calculate the difference (subtract)

j ≥ -37

3 0
3 years ago
Read 2 more answers
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