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timurjin [86]
3 years ago
10

Does anyone know the answer?

Mathematics
2 answers:
Alex787 [66]3 years ago
4 0

Answer:

its a

Step-by-step explanation:

7×8-10=46

5×8+6=46

kozerog [31]3 years ago
3 0

Answer:

8

Step-by-step explanation:

You might be interested in
5x – 2x + 7 – x = ?x + ?
fomenos

Step-by-step explanation:

5x – 2x + 7 – x = ?x + ?

I need the answer for "no solution" and "infinite solutions".

NO SOLUTION:

no solution because any value you give to x is not solvable, it remains +7

5x – 2x + 7 – x = ?x + ?

2x = 2x + 7

INFINITE SOLUTION

infinite solutions because any value you give to x is solvable

5x – 2x + 7 – x = ?x + ?

5x – 2x + 7 – x = 2x + 7

2x + 7 = 2x + 7

8 0
2 years ago
A tuition scale for a state university shows an increase of $1,100 each year. If the initial cost was $27,000. What will the cos
oksian1 [2.3K]

If each years cumulate an increase of 1100 dollars, then the cost after 22 years will be the base cost (27000) plus 22 increases (22*1100), for a total of

27000 + 22\cdot 1100 = 27000 + 24200 = 51200

This relates to arithmetic series as follows: a series is arithmetic if, given a starting element x_0, every next element is given by adding a fixed number, called common difference, r. So, the first terms are

  • a_0 = x_0
  • a_1 = x_0 + r
  • a_2 = x_1 + r = (x_0+r) + r = x_0 + 2r
  • a_3 = x_2 + r = (x_0+2r) + r = x_0 + 3r
  • a_4 = x_3 + r = (x_0+3r) + r = x_0 + 4r

So, you can see that the element x_n is obtained by adding n times the common ratio to the starting element.

Since the element a_n represents the cost after n years, we are interested in the element

a_{22} = x_0 + 22r = 27000 + 22\cdot 1100 = 512000

As we had already calculated.

7 0
3 years ago
Midsegments geometry acellus pls helppfpfpff
Anika [276]

Answer:

BC = 28

Step-by-step explanation:

The midsegment DF is half the measure of the third side BC , then

BC = 2 × DF = 2 × 14 = 28

5 0
3 years ago
The focus of a parabola is (-3,-5) The directrix of the parabola is y=2
cricket20 [7]

Check the picture below.

so the focus point is there, and the directrix is above it, meaning is a vertical parabola and is opening downwards, since the parabola opens up towards the focus.

now, the vertex is half-way between those two guys, at a "p" distance from either one, if we move over the y-axis from -5 to +2, we have 7 units, half-way is 3.5 units, and that puts us at -1.5 or -1½, as you see in the picture, so the vertex is then at (-3 , -1½).

so the distance from the vertex to the focus point  is then 3½ units, however since the parabola is opening downwards, "p" is negative, thus "p = 3½".

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{using this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{cases} h=-3\\ k=-\frac{3}{2}\\[0.7em] p=-\frac{7}{2} \end{cases}\implies 4\left( -\cfrac{7}{2} \right)\left[ y-\left(-\cfrac{3}{2} \right) \right]=\left[ x-\left( -3 \right) \right]^2 \\\\\\ -14\left( y+\cfrac{3}{2} \right)=(x+3)^2\implies y+\cfrac{3}{2} =-\cfrac{(x+3)^2}{14} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{14}(x+3)^2-\cfrac{3}{2}~\hfill

4 0
3 years ago
If 5/6 is divided by a certain fraction a/b, the result is 1/4. What is the fraction a/b?
vodka [1.7K]
The fraction would be 10/3.  Hope this helps!
3 0
3 years ago
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