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2 years ago

Write an equation for the statement. Then, solve the equation:

Mathematics

1 answer:

Diano4ka-milaya [45]2 years ago

4 0

Answer:

V = 125.6 in³

Step-by-step explanation:

let V be volume, h the height and r the radius, then the equation relating the quantities is

V = khr² ← k is the constant of variation

To find k use the condition V = 402.12, h = 8, r = 4

402.12 = k × 8 × 4² = 128k ( divide both sides by 128 )

3.14 = k [ note 3.14 is π )

V = 3.14hr² ← equation of variation [ V = πr²h ]

Given r = 2 and h = 10, then

V = 3.14 × 10 × 2² = 3.14 × 40 = 125.6

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(23/7+61/3)_34/3 what the answer

Keith_Richards [23]

23/7+61/3 is done first due to PEMDAS
so the lcm of 7 and 3 is 21
So 23*3 + 61*7 divide the whole by 21 which is 7*3
The answer will come out to 496/21
Then outside the bracket the whole is times 34/3
So 34/3*496/21=
16864/64
We can’t simplify it more so that’s the answer

3 0

2 years ago

Carlos graphs the equations y = 0.5x2 + 3 and y = –4x2 + 24x – 35 and generates the graph below. Which conclusion is supported b

never [62]

Answer:

It has no solution

Step-by-step explanation:

Here we have to draw the graph of y = 0.5x^2 + 3 and y = -4x^2 + 24x - 35.

I have attached the graph of these two functions.

Since the graphs of the functions didn't cut each other.

Therefore, answer is "it has no solution."

Hope this will helpful.

Thank you.

3 0

3 years ago

Read 2 more answers

g An urn contains 10 balls: 4 red and 6 blue. A second urn contains 16 red balls and an unknown number of blue balls. A single b

Fed [463]

Answer:

Therefore the of blue in the second urn is 4.

Step-by-step explanation:

Let second urn contain x number of blue ball .

Urn Red Ball Blue Ball Total Ball

1 4 6 10

2 16 x 16+x

Getting a red ball from first urn is $P(R_1)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{4}{10}$

Getting a blue ball from first urn is $P(B_1)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {6}{10}$

Getting a red ball from second urn is $P(R_2)=\frac{\textrm {Number of red ball}}{\textrm {Total ball}}$ $=\frac{16}{16+x}$

Getting a blue ball from second urn is $P(B_2)=\frac{\textrm {Number of blue ball}}{\textrm {Total ball}}$ $=\frac {x}{16+x}$

Getting two red balls from first and second urn is $=\frac{4}{10}\times \frac{16}{16+x}$

$=\frac{32}{5(16+x)}$

Getting two blue balls from first and second urn is $=\frac{6}{10}\times \frac{x}{16+x}$

$=\frac{3x}{5(16+x)}$

The probability that both balls are the same in color is $=\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}$

Given that the probability that both balls are the same in color is 0.44.

According to the problem,

$\frac{32}{5(16+x)}+\frac{3x}{5(16+x)}=0.44$

$\Rightarrow \frac{32+3x}{5(16+x)} =0.44$

$\Rightarrow \frac {32+3x}{(80+5x)} =0.44$

$\Rightarrow 32+3x =0.44(80+5x)$

$\Rightarrow 32+3x =35.2 +2.2x$

$\Rightarrow 3x -2.2 x= 35.2 -32$

$\Rightarrow 0.8x= 3.2$

$\Rightarrow x = 4$

Therefore the of blue in the second urn is 4.

5 0

3 years ago

Help I will be marking brainliest!!!

Talja [164]

48.. i don’t have the work but hopefully someone else does

8 0

2 years ago

Read 2 more answers

Can someone please check if this is correct?

Solnce55 [7]

Answer:

Just two corrections! See attached image.

Step-by-step explanation:

The product of 8 and b taken from 10 means begin with 10 and subtract 8b from it.

8 times the difference of 10 and b means find 10 - b first, then multiply by 8.

7 0

2 years ago