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Oliga [24]
3 years ago
5

The price, e, of an entertainment system at extreme electronics is $220 less than twice the price, u, of the same system at ultr

a electronics. the difference in price between the system at extreme electronics and ultra electronics is $175.
which system of linear equations can be used to determine the price of the system at each store?
Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer: The price of system at extreme electronics is $570 and the price of system at ultra electronics is $395.

Step-by-step explanation:

Let the price of the system at the ultra electronics be u

Let the price of the system at extreme electronics be e

According to question, we have

2u-e=220\\\\and\\\\e-u=175

Now, using the substitution method, we will solve the above system of equations.

e-u=175\\\\e=175+u

Now, put the value of u in the first equation :

2u-e=220\\\\2u-(175+u)=220\\\\2u-175-u=220\\\\u-175=220\\\\u=220+175\\\\u=\$395

Now, we put the value of u in the equation which is given by:

e=175+u\\\\e=175+395\\\\e=\$570

Hence, the price of system at extreme electronics is $570 and the price of system at ultra electronics is $395.

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Savatey [412]

Answer:

a\cdot b\cdot c=\frac{15}{4}

Step-by-step explanation:

Vertex is the minimum or maximum point of parabola

Vertex of parabola is (h,k)

Therefore, from given graph (-3,-2) is the lowest point.

Vertex of parabola is at (-3,-2).

Standard equation of parabola

y-k=a(x-h)^2

Substitute the values

y-(-2)=a(x-(-3))^2=a(x+3)^2

y+2=a(x+3)^2

(-1,0) lies on the parabola.

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0+2=a(-1+3)^2=4a

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Now, using the value of a

y+2=1/2(x+3)^2=1/2(x^2+6x+9)

y+2=\frac{1}{2}x^2+3x+\frac{9}{2}

y=\frac{1}{2}x^2+3x+\frac{9}{2}-2

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y=\frac{1}{2}x^2+3x+\frac{5}{2}

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a=\frac{1}{2}, b=3, c=5/2

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a\cdot b\cdot c=\frac{15}{4}

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