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2 years ago

Question 7 Find the area of the figure,

Mathematics

1 answer:

photoshop1234 [79]2 years ago

8 0

Answer:

Try splitting the figure up and use the basic area formulas to help u

Step-by-step explanation:

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What the area of this shape

Rudiy27

Answer:it is 6,930

Step-by-step explanation:

3 0

3 years ago

In old-growth forests of douglas fir, the spotted owl dines mainly on flying squirrels. If we left When the initial population i

Delicious77 [7]

Answer: There are 667 owls for every 1000 squirrels.

Step-by-step explanation:

Since we have given that

Number of owls = 30

Number of squirrels = 45

If the number of owls and squirrels will continue to increase.

If there are 1000 squirrels, then the number of owls would be

$\dfrac{30}{45}=\dfrac{x}{1000}\\\\x=\dfrac{30\times 1000}{45}\\\\x=666.67\\\\x\approx 667$

Hence, there are 667 owls for every 1000 squirrels.

5 0

3 years ago

In a circle with a radius of 7 feet, the radian measure of the central angle subtended by an arc with a length of 4 feet is . Th

ivann1987 [24]

We know that
length of a sector=[∅]*r--------> when ∅ is in radians
so
∅=length of a sector/r
for r=7 ft
length of a sector=4 ft
∅=4/7-----> 0.57 radians

the answer part 1) is 0.57 radians

part 2)
area of a sector=(∅/2)*r²--------> when ∅<span> is in radians
</span>area of a sector=(4/7/2)*7²-----> (4/14)*49----> 14 ft²

the answer Part 2) is 14 ft²

3 0

3 years ago

70% of x is 63. Write an equation to find the value of x, and solve the equation. What is the value of x?

melisa1 [442]

Answer:

70%of x = 63

70/100 × x = 63

x=63×100/70

x=90

Step-by-step explanation:

7 0

3 years ago

Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3

KatRina [158]

Answer:

Step-by-step explanation:

$g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}$

4 0

3 years ago