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4 years ago

Elisha is a photographer and charges a set fee to photograph weddings. This is an example of _____ income.

2 answers:

6 0

<span>Elisha is a photographer and charges a set fee to photograph weddings. This is an example of Passive income. Passive income because it is a limited partnership and is not stable income.</span>

emmasim [6.3K]4 years ago

3 0

The following "Verified" answer is wrong. On Financial math, The answer is <u>B. Earned</u>.

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-9x-3y= -2<br> 3x-y= -4<br><br> Solve for x and y.

Alexxx [7]

Try it on the app photomath

4 0

4 years ago

Derivative of these questions<br>

shtirl [24]

Answer: $\bold{y'=\dfrac{1}{2(a-b)^2}\bigg(\dfrac{1}{\sqrt{x+a}}+\dfrac{1}{\sqrt{x+b}}\bigg)}$

<u>Step-by-step explanation:</u>

$y=\dfrac{1}{\sqrt{x+a}-\sqrt{x+b}}\\\\\\\text{Rationalize the denominator:}\\y=\dfrac{1}{\sqrt{x+a}-\sqrt{x+b}}\bigg(\dfrac{\sqrt{x+a}+\sqrt{x+b}}{\sqrt{x+a}+\sqrt{x+b}}\bigg)\\\\\\y=\dfrac{\sqrt{x+a}+\sqrt{x+b}}{x+a-x-b}\\\\\\y=\dfrac{\sqrt{x+a}+\sqrt{x+b}}{a-b}\\\\\\\text{Apply the derivative (derivative of the numerator (top) divided by the}\\\text{denominator (bottom) squared).}$

$\text{Derivative of }\sqrt{x+a}\quad \rightarrow \quad (x+a)^{\frac{1}{2}}\quad = \quad \dfrac{1}{2}(x + a)^{-\frac{1}{2}}\\\\\text{Derivative of }\sqrt{x+b}\quad \rightarrow \quad (x+b)^{\frac{1}{2}}\quad = \quad \dfrac{1}{2}(x + b)^{-\frac{1}{2}}\\\\\\\text{Derivative of}\ \dfrac{\sqrt{x+a}+\sqrt{x+b}}{a-b}:\\\\= \dfrac{\dfrac{1}{2}(x + a)^{-\frac{1}{2}}+\dfrac{1}{2}(x + b)^{-\frac{1}{2}}}{(a-b)^2}$

$\text{Factor out }\dfrac{1}{2}\ \text{from the numerator:}\\\\\dfrac{(x+a)^{-\frac{1}{2}}+(x+b)^{-\frac{1}{2}}}{2(a-b)^2}\\\\\\\text{Move the terms with negative exponents to the denominator:}\\\\=\dfrac{1}{2(a-b)^2}\bigg(\dfrac{1}{\sqrt{x+a}}+\dfrac{1}{\sqrt{x+b}}\bigg)$

3 0

3 years ago

Translation can be written in ordered pair notation true or false

Andrew [12]

True. Translation can be written in ordered pair notation.

5 0

3 years ago

Solve for the value of r. (8r+6)° (9r-7)

lukranit [14]

Answer:

r = 13

Step-by-step explanation:

these angles are vertical and are congruent

8r + 6 = 9r - 7

6 = r - 7

13 = r

8 0

3 years ago

Please Help Me, This Is So Difficult.

Julli [10]

The maximum revenue would be $9600 and would be achieved using 0 nonstop flights and 12 two-stop flights.

<h3>How to define the variables</h3>

Let x = number of non-stop airplanes

Let y = number of two-stop airplanes

<h3>The system of linear inequalities</h3>

Using the variables in (a), we have the following constraints

Total passenger constraint: 150x + 100y <= 1500

Total Airplanes constraint: x + y <= 12

<h3>Graph the feasible region.</h3>

In (b), we have the following system of linear inequalities

150x + 100y <= 1200

x + y <= 12

See attachment for the graph

<h3>The objective function</h3>

The objective function of the constraints is:

Max z = 1100x + 800y

<h3>The maximum revenue</h3>

From the graph of the function, the optimal solution is:

(x,y) = (0,12)

So, the maximum revenue is:

z = 1100x + 800y

z = 1100*0 + 800*12

z = 9600

Hence, the maximum revenue is $9600

Read more about objective functions at:

brainly.com/question/16826001

6 0

2 years ago