Wave of option A has the highest frequency.
Option A.
<h3><u>Explanation:</u></h3>
Frequency is defined as the total number of complete waves in an unit time. A complete wave consists of a complete cycle of the amplitudes of waves.
In all the figures, we see transverse waves. They have the mean position denoted by a straight line, and the waves do oscillate up and down to complete a full cycle. The most number of waves in a given time has the highest frequency. If we count the full number of waves in the particular given time, Wave A has 5.75 complete waves, wave B has 3.5 complete waves, wave C has 2 complete waves and the wave D has 2.75 complete waves. So the wave A has highest number of complete oscillations in a given time. So wave A has highest frequency.
Answer:
True
Explanation:Hope it helps! :)
<span>Example of Trisomy 21 detected</span>... <span>the presence , which is found in Down syndrome, is calledtrisomy 21.</span> ... <span>Of these, Trisomy 21 and Trisomy 18 are the most common.</span> ... <span>XXX (Triple X syndrome); XXY (Klinefelter syndrome); XYY</span> ... <span>Turner syndrome (XO).
so i think all are right</span>
Answer:
- Parental cross = Cch x chch
- F1 = 1/2 Cch (agouti coat); 1/2 chch (albino coat) >> 1:1 phenotypic ratio
Punnett square:
ch ch
C Cch Cch
ch chch chch
Explanation:
A heterozygous individual is an individual who has two different gene variants (i.e., alleles) at a particular <em>locus</em>. In this case, individuals having the "agouti coat" trait are heterozygous carrying both 'C' and 'ch' alleles. On the other hand, a homo-zygous individual has the same allele at a given <em>locus</em> (here, the 'chch' genotype associated with the albino phenotype). Therefore, as observed in the Punnett Square above, when a heterozygous parent is crossed with a homo-zygous recessive parent for a single gene, alleles segregate in the gametes of both parents so an expected 1:1 phenotypic ratio will be observed.
mitochondria and the Golgi apparatus i hope that's helps
