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3 years ago

Can anyone help me lol?

Mathematics

1 answer:

Olin [163]3 years ago

5 0

Answer:

Approximately 143

Step-by-step explanation:

The fraction that is women is 19/(19 + 81). Multiply the total number (750) by this fraction, and get the total number of women.

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What is the GCF for 21 and 40

Rainbow [258]

The GCF is 1

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3 years ago

You and your friends bought some movie tickets. Each movie ticket cost $6.32 per person. You also spent $14.00 on popcorn. If yo

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Answer:

Step-by-step explanation:

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Zadanie optymalizacyjne z matematyki. Proszę o rozwiązanie i wyjaśnienie

Yakvenalex [24]

Volume of the pyramid:

$V=\dfrac{s^2h}3$

Perimeter of the cross-section:

$40=\sqrt2\,s+2\sqrt{\dfrac{s^2}2+h^2}=\sqrt2\left(s+\sqrt{s^2+2h^2}\right)$

$\implies h=\sqrt{\dfrac{(20\sqrt2-s)^2-s^2}2}=\sqrt{400-20\sqrt2\,s}$

Area of the cross-section:

$P=\dfrac12(\sqrt2\,s)h=\dfrac{sh}{\sqrt2}$

$\implies P=\dfrac{s\sqrt{400-20\sqrt2\,s}}{\sqrt2}=s\sqrt{200-10\sqrt2\,s}$

First derivative test:

$\dfrac{\mathrm dP}{\mathrm ds}=\dfrac{20\sqrt2-3s}{\sqrt{4-\dfrac{\sqrt2}5s}}=0\implies s=\dfrac{20\sqrt2}3$

Then the height of the cross-section/pyramid is

$h=\sqrt{400-20\sqrt2\,s}=\dfrac{20}{\sqrt3}$

The volume of the pyramid that maximizes the cross-sectional area $P$ is

$V=\dfrac{\left(\frac{20\sqrt2}3\right)^2\frac{20}{\sqrt3}}3=\dfrac{16000}{27\sqrt3}$

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3 years ago

You purchase 2 action figures per week. You have 48 action figures, which is 75% of the total number of action figures you need

LiRa [457]

Answer:

Step-by-step explanation:

Let the total number of action figures = x

75% of x = 48

$\dfrac{75}{100}*x=48\\\\Multiply \ by \ 100\\\\75*x =48*100\\\\Divide \ by \ 75\\\\x=\dfrac{48*100}{75}\\\\\\x=16*4\\\\x= 64$

Remaining action figures need to be collected = total figures - number of action figures I have

= 64 - 48 = 16

Number of weeks = 16 ÷ 2 = 8

It will take 8 weeks to collect 16 action figures.

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2 years ago

What is (2w-9) + (-4w-5)

Scrat [10]

Answer:

-2w-14

Step-by-step explanation:

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