Answer: Joe will spend 33.33hours travelling in the train
Explanation:
We will use two equations of motion to solve this problem.
At first, we need to know the acceleration of the train. Using v(square) = u(square) + 2×a×s
Where v is the average speed of the train; 42.
u is the initial speed; which is zero since there is no speed when there is no motion.
a is the train's acceleration; we have to calculate this.
s is the distance between Joe's hometown and Georgetown; 350 miles
Making a the subject of the formula and knowing u =0, the equation reduces to
a=v(square)/2×s
Plugging the numbers
a= 42(square)/2×350
a=2.52 mph(square)
Furthermore, using another equation of motion to obtain time of travel between Joe's hometown and Georgetown
s=(u×t) + 1/2(a×t(square))
u=0 (from previous explanation) making u×t=0
s=350mph
a= 2.52mph(square)
Making t the subject of the formula
t= square root((2×s)/a)
t=square root((2×350)/2.52)
Solving the equation,
t=square root(277.778)
t=16.67 hours
Since it is a to and fro journey, we will multiply 16.67 hours by to cater for the return journey.
Total time =2×16.67
Total time= 33.33 hours
