Question

Find the missing side lengths. Leave your answer as radicals in simplest form.

Answer 1

Answer:

$x = 4\sqrt{2}$

$y = 2\sqrt{6}$

Step-by-step explanation:

$sin 30 = \frac{opposite}{hypotenuse}$

    $\frac{1}{2}= \frac{2\sqrt{2} }{x}\\\\1 \times x = = 2\sqrt{2} \times 2\\\\x = 4\sqrt{2}$

$cos 30 =\frac{adjacent}{ hypotenuse}$

   $\frac{\sqrt{3} }{2} = \frac{y}{4\sqrt{2} }\\\\\frac{\sqrt{3} }{2} \times 4\sqrt{2} = y\\\\2\sqrt{6} = y$