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<h2>Answer:</h2><h2></h2>
//import the Random and Scanner classes
import java.util.Random;
import java.util.Scanner;
//Begin class definition
public class ChangeUp {
//Begin the main method
public static void main(String args[]) {
//Initialize the empty array of 6 elements
int [] numbers = new int [6];
//Call to the populateArray method
populateArray(numbers);
} //End of main method
//Method to populate the array and print out the populated array
//Parameter arr is the array to be populated
public static void populateArray(int [] arr){
//Create object of the Random class to generate the random index
Random rand = new Random();
//Create object of the Scanner class to read user's inputs
Scanner input = new Scanner(System.in);
//Initialize a counter variable to control the while loop
int i = 0;
//Begin the while loop. This loop runs as many times as the number of elements in the array - 6 in this case.
while(i < arr.length){
//generate random number using the Random object (rand) created above, and store in an int variable (randomNumber)
int randomNumber = rand.nextInt(6);
//(Optional) Print out a line for formatting purposes
System.out.println();
//prompt user to enter a value
System.out.println("Enter a value " + (i + 1));
//Receive the user input using the Scanner object(input) created earlier.
//Store input in an int variable (inputNumber)
int inputNumber = input.nextInt();
//Store the value entered by the user in the array at the index specified by the random number
arr[randomNumber] = inputNumber;
//increment the counter by 1
i++;
}
//(Optional) Print out a line for formatting purposes
System.out.println();
//(Optional) Print out a description text
System.out.println("The populated array is : ");
//Print out the array content using enhanced for loop
//separating each element by a space
for(int x: arr){
System.out.print(x + " ");
}
} //End of populateArray method
} //End of class definition
<h2>Explanation:</h2>
The code above is written in Java. It contains comments explaining the lines of the code.
This source code together with a sample output has been attached to this response.
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.