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dybincka [34]
3 years ago
9

I’ll mark you brainlist

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0
1 up and 5 to left :)
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1 x 0 = 0?
Alexxandr [17]
Both

1 times a=a
and 
b times 0=0
3 0
3 years ago
Read 2 more answers
Graphing rational functions. I need help asap!!!!
Anastaziya [24]

Answer:

1.  

Vert. asymptote: x = {-3, 2}

Horiz. asymptote: y = 0

x-int: None

Question 3.

a. There is no hole

b. Vert. asymptote: x = {-2, 2}

c. f(x) = 0: x = {0, -1/2}

d. The graph has no hole at (-2, 4)

Question 4.

a. Vert. asymptote: x = {-2, 2}

b. f(x) = 0: x = {0, -1/2}

c. Horizontal asymptote: y = 2

d. The graph has no hole

I'm a bit confused.  Some of the things stated in the question aren't true like how there are holes in places where there aren't.

6 0
3 years ago
Y
qaws [65]

Answer:

(-2, 0.5) first

Step-by-step explanation:

X (-4, 1) → X' (-4*0.5, 1*0.5)

X'(-2, .5)

5 0
3 years ago
Please help me with this pleaseee
torisob [31]

Answer:

x = 88.2

Step-by-step explanation:

The angle at the top of the triangle = 90° - 10° = 80°

and the left side of the triangle is x ( opposite sides of a rectangle )

Using the tangent ratio in the right triangle

tan80° = \frac{opposite}{adjacent} = \frac{500}{x}

Multiply both sides by x

x × tan80° = 500 ( divide both sides by tan80° )

x = \frac{500}{tan80} ≈ 88.2

5 0
3 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
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