Answer:
A
Step-by-step explanation:
We have the equation:
Take the derivative of both sides with respect to x:
![\frac{d}{dx}[x^2+xy-3y]=\frac{d}{dx}[3]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5E2%2Bxy-3y%5D%3D%5Cfrac%7Bd%7D%7Bdx%7D%5B3%5D)
Implicitly differentiate:
Solve for dy/dx:
Divide:
To find dy/dx at (2, 1), substitute 2 for x and 1 for y. So:
Hence, our answer is A.
2/5y + 3/5 did that work?
Answer:
For less than 7 uniforms.
Step-by-step explanation:
The first company she called charges $70 per uniform.
So, the cost of x uniforms will be $70x.
The second company she called charges $280 plus $30 per uniform.
So, the cost of x uniform will be $(280 + 30x).
Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as
70x < 280 + 30x
⇒ 70x - 30x < 280
⇒ 40x < 280
⇒ x < 7
Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)
Y=(-x*x)-4x+3
y=-(x^2+4x-3)
4+y=-(x^2+4x+4)+3
y+4=-(x-2)^2.) +3
-4. -4
y=-((x-2)^2)-1
Answers:
Vertex: (2,-1)
AOS:x = 2
Domain: All Real Numbers
Range:[-1,Infinity)
Letter D
1-sin^2(x) = cos^2(x)
= sin^2(x)/cos^2(x)
= tan^2(x)
