Answer:
R's share = 306
Explanation:
Sum of ratio = 1/3 + 1/2 + 1/5
LCM = 30
Sum of ratio = (10 + 15 + 6) / 30 = 31 /30
Profit to be shared = 1581
P = 1/3 ; Q = 1/2 ; R = 1/5
Share of R :
(Total profit / sum of ratio) * R ratio
[1581 / (31/30)] * 1/5
(1581 / 1 * 30/31) * 1/5
51 * 30 * 1/5
51 * 6 = 306
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An example I believe of relational context is when I was out with my son on the weekend (he has a developmental disability) and we had agree I would buy him a 1/2 sub sandwich the day before but then he said I would like a McFlurry so I said okay and then he said so you mean I can have a McFlurry and a sub and I thought oh oh I stuck my foot in it so I said but it must be only a 1/2 sub so he said no I want a full sub then and no mcflurry so I agreed so from the original 1/2 sub idea the idea evolved to a full sub which was affected by the warm sunny summery weather in the afternoon and seeing people lined up at ice cream shops so the idea developed in relation to the weather, how hungry he was and the social aspect people buying ice cream.
Answer:
See Explanation
Explanation:
Given
The attached function
What the recursion does is that; it adds up individual digits from N to 0
Solving (a): Each output when N = 6
For N = 6.
The function returns the following values:
f(6) = 6
Then: 6 + f(5)
Then: 6 + 5 + f(4)
Then: 6 + 5 + 4 + f(3)
Then: 6 + 5 + 4 + 3 + f(2)
Then: 6 + 5 + 4 + 3 + 2 + f(1)
Then: 6 + 5 + 4 + 3 + 2 + 1 + f(0)
Then: 6 + 5 + 4 + 3 + 2 + 1 + 0 = 21
Solving (b): The output when N = 7
Using the same process in (a) above.
The output is 28
Answer:
"double result=6.759;" is the correct answer for the above question.
Explanation:
- In c-programming language, the double is a data type which stores the decimal value up to 6 decimal point.
- This data type takes 8 bytes space in memory when it is used in the c-programming language.
- When the user wants to declare the double data type, then he should need to declare by the help of the following syntax-- double variable_name_or _identifier_name;
- When the user wants to declare the double data type and initialize the value on its then he can do this with the help of the following syntax--double variable_name_or _identifier_name= value_which_needs_to_store;
- The above question asked the one-line statement which declares the result variable of double data type and initializes the "6.759" value on its then he can do this by the help of "double result=6.759;" statement which is described above. Hence the answer is "double result=6.759;".
