Question

A bag contains 18 balls to green five black eight blue one brown one red and one white if 17 balls of a move from the bag at random what is the probability that a brown ball has been removed

Answer 1

Answer:

$P(Brown) = 0.0556$ or $P(Brown) = \frac{1}{18}$

Step-by-step explanation:

Given

$Total = 18$

$Green = 2$

$Black = 5$

$Blue = 8$

$Brown = 1$

$Red = 1$

$White = 1$

Required

Determine the probability of selecting a brown ball

This is calculated as thus:

$P(Brown) = \frac{Brown}{Total}$

Substitute values for Brown and Total

$P(Brown) = \frac{1}{18}$

The answer can be in fraction or solved further as;

$P(Brown) = 0.0556$