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3 years ago

PLEASE HELP ME ILL BRAINLIEST YOU

Mathematics

2 answers:

german3 years ago

5 0

Answer:

x = 30

Step-by-step explanation:

The angles were not very clear in this diagram. However, I'm assuming that the angle is the bottom right of the written terms. Since lines l and m are parallel, the two angles are equal and corresponding to each other.

Hence, 6x - 63 = 4x - 3

Subtract both sides by 4x and you will get 2x - 63 = -3.

Now, add 63 on both sides to get 2x = -3+63 = 60.

Hence, x = 60/2 = 30

sweet-ann [11.9K]3 years ago

4 0

Answer:

C. 30

Step-by-step explanation:

These angles are known as corresponding angles meaning they are equal. Knowing this, we can set up the following equation.

6x - 63 = 4x - 3

2x - 63 = -3

2x = 60

x = 30

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3 years ago

A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o

Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(X $E(X_{k}) = n_{k} * p_{k}$

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = $\frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}$

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= $\frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\$ = 0.00022

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= $\frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\$ = 0.000001

P(X₁≤2) = $\frac{22!}{0!} * 0.08^{0} * (0.92)^{22}$ + $\frac{22!}{1!} * 0.08^{1} * (0.92)^{21}$ + $\frac{22!}{2!} * 0.08^{2} * (0.92)^{20}$ = 0.7442

I hope you have a SUPER day!

8 0

3 years ago

Evaluated to square

denis-greek [22]

Step-by-step explanation:

The square root of a number is a number that you can square to get it, that is, a number that you can multiply by itself to get the number. So, 2 is a square root of 4, because 2 x 2 = 4, and 3 is a square root of 9, because 3 x 2 = 9.

3 0

3 years ago

A computer consulting firm presently has bids out on three projects. Let Ai = {awarded project i}, for i = 1, 2, 3, and suppose

Karo-lina-s [1.5K]

Step-by-step explanation:

The data below is what was provided in the question and it is what I solved the question with

P(A1) = 0.23

P(A2) = 0.25

P(A3) = 0.29

P(A1 n A2 ) = 0.09

P(A1 n A3) = 0.11

P(A2 n A3) = 0.07

P(A1 n A2 n A3) = 0.02

P(A2|A1) = P(A1 n A2)/P(A1)

= 0.09/0.23

= 0.3913

We have 39.13% confidence that event A2 will occur given that event A1 already occured

b.)

P(A3 n A3|A1) = P(A2 n A3)n A1)/P(A1)

= 0.02/0.23

= 0.08695

We have about 8.7% chance of events A2 and A3 occuring given that A1 already occured.

P(A2 u A3|A1)

= P(A1 n A2)u(A1 n A3)/P(A1)

= P( A1 n A2) + P(A1 n A3) - P(A1 n A2 n A3) / P(A1)

= (0.09+0.11-0.02)/0.23

= 0.18/0.23

= 0.7826

We have 78.26% chance of A2 or A3 happening given that A1 has already occured.

6 0

3 years ago

Please help Solve show all of your work and check your solution 5. 5/6 x =4 2. 2/5 x =42

rosijanka [135]

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 5

$\frac{5}{6}x=4\\ \\\frac{5}{6}x*6=4*6\\ \\5x=24\\\\\frac{5x}{5}=\frac{24}{5}\\ \\ x=\frac{24}{5}$

Check solution:

$\frac{5}{6}(\frac{24}{5})\stackrel{?}{=}4\\ \\\frac{5*24}{6*5}\stackrel{?}{=}4\\ \\\frac{120}{30}\stackrel{?}{=}4\\ \\4=4$

Problem 6

$\frac{2}{5}x=42\\ \\\frac{2}{5}x*5=42*5\\ \\2x=210\\\\\frac{2x}{2}=\frac{210}{2}\\ \\ x=105$

Check solution:

$\frac{2}{5}(105)\stackrel{?}{=}42\\ \\\frac{2*105}{5}\stackrel{?}{=}42\\\\\frac{210}{5}\stackrel{?}{=}42\\\\42=42$

4 0

3 years ago