How much 9% saline solution should be mixed with 80 Cc of a 17% saline solution to produce a 13% saline solution?
1 answer:
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Let
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is
</span>the rectangle's length is 16 cm
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is
</span>the rectangle's length is 16 cm