Answer:
68
Step-by-step explanation:
you have to add to 180 and 68+112=180
Answer is D
After dilation the image remain same but it is stretched or shrinked to the original size.
That means the ratio of the sides and the angles between the sides remain same .
Here we did dilation of ABCD which made it to EFGH.
Hence the ratio of the corresponding sides of the original rectangle ABCD should remain same even after dilation.
the corresponding sides are : AB and EF
BC and FG
CD and GH
DA and HE
* Let us find ratio of the sides AB and BC
given that AB= 10 and BC= 14
AB/BC= 10/14 = 5 /7 ( 10 and 14 both are multiple of 2 so we reduced them by a factor of 2 )
* the raio of the corresponding sides EF and FG should be same ( 5/7)
in the option D EF= 25 and FG= 35
so EF/FG= 25/35 = 5 /7 ( both are multiple of 5 so we reduced them by the factor of 5 )
Since ratio of the corresponding sides are coming out to be same for the EFGH given in option D it should be the dilation of the ABCD
Answer:

Step-by-step explanation:
Method 1:
Arithmetic sequence is in the form

d is the common difference, can be found by:

Subtituting the
and 
You get:

Method 2 (Mathematical induction):
Assume it is in form 
Base step: 
Inducive hypophesis: 
GIven: 

Proved by mathematical induction

Answer:
False
Step-by-step explanation:
The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value.
Answer:
The answer to your question is below
Step-by-step explanation:
Question 1
x = 5 Equation l
2x + y = 10 Equation ll
- Substitute Equation l in equation ll
2(5) + y = 10
y = 10 - 10
y = 0
- Solution (5, 0)
Question 2
x + 16y = 20 Equation l
x = 4y Equation ll
Substitute equation ll in equation l
4y + 16y = 20
20y = 20
y = 20/20
y = 1
-Find x
x = 4(1)
x = 4
-Solution
(4, 1)
Question 3
2x + 8y = 20 Equation l
x = 2 Equation ll
-Substitute equation ll in equation l
2(2) + 8y = 20
4 + 8y = 20
8y = 20 - 4
8y = 16
y = 16/8
y = 2
- Solution
(2, 2)