Question

The right triangle shown has one leg of length 5 centimeters and a hypotenuse of length 13 centimeters a) find the length of the other leg b) what is the perimeter of the triangle c) what is the area of the triangle

Answer 1

A) By Pythagoras' Theorem  x^2 = 13^2 - 5^2    where x = length of the other leg.  x^2 = 169 - 25 = 144 so x = 12. cms.

b) perimeter = 5 + 12 + 13 = 30 cms

c) Area of triangle = product of the 2 legs  = 5*12 = 60 cm^2.