The right triangle shown has one leg of length 5 centimeters and a hypotenuse of length 13 centimeters a) find the length of the
other leg b) what is the perimeter of the triangle c) what is the area of the triangle
1 answer:
A) By Pythagoras' Theorem x^2 = 13^2 - 5^2 where x = length of the other leg. x^2 = 169 - 25 = 144 so x = 12. cms.
b) perimeter = 5 + 12 + 13 = 30 cms
c) Area of triangle = product of the 2 legs = 5*12 = 60 cm^2.
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