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Lesechka [4]
3 years ago
10

The access code for a​ car's security system consists of digits. The first digit cannot be and the last digit must be . How many

different codes are​ available?
Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Complete Question

The access code for a car's security system consists of 6 digits, the first digit cannot be 8 and the last digit must be odd, how many different codes are available

Answer:

There are 450000 possible different codes

<em></em>

Step-by-step explanation:

Given

Code = 6 digits

First = All but 8

Last = Odd

Required

Determine the possible number of codes

Analyzing each individual digit that makes up the code.

First: can be any of 0,1,2,3,4,5,6,7,9 ----- 9 possible numbers

Second, Third, Fourth and Fifth can be any of 0,1,2,3,4,5,6,7,8,9 since there's no restriction ----- 10 possible numbers

Last can be any of: 1,3,5,7,9 ----- 5 possible numbers

So, the number of possible selections is:

Selection = 9 * 10 * 10 * 10 * 10 *5

Selection = 450000

<em>Hence, there are 450000 possible different codes</em>

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Step-by-step explanation:

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loris [4]
I got (-6.28, -0.76). 

Step 1.) Write out the problems
   -2x=8-6y
   -15x=21-6y

Step 2.) Pick a problem and solve for X
   -2x=8-6y =  x=-4-3y

Step 3.) Plug in the x
    (-15)(-4-3y)= 21-6y
    60 + 45y= 21-6y

Step 4.) Solve for y
    y=-0.76

Step 5.) Plug in the y value into one of the equations
    -2x= 8- 6(-0.76)
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Step 6.) Check your answers
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Step 7.) Write it out
   (-6.28,-0.76)
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