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Lesechka [4]
2 years ago
10

The access code for a​ car's security system consists of digits. The first digit cannot be and the last digit must be . How many

different codes are​ available?
Mathematics
1 answer:
Semenov [28]2 years ago
7 0

Complete Question

The access code for a car's security system consists of 6 digits, the first digit cannot be 8 and the last digit must be odd, how many different codes are available

Answer:

There are 450000 possible different codes

<em></em>

Step-by-step explanation:

Given

Code = 6 digits

First = All but 8

Last = Odd

Required

Determine the possible number of codes

Analyzing each individual digit that makes up the code.

First: can be any of 0,1,2,3,4,5,6,7,9 ----- 9 possible numbers

Second, Third, Fourth and Fifth can be any of 0,1,2,3,4,5,6,7,8,9 since there's no restriction ----- 10 possible numbers

Last can be any of: 1,3,5,7,9 ----- 5 possible numbers

So, the number of possible selections is:

Selection = 9 * 10 * 10 * 10 * 10 *5

Selection = 450000

<em>Hence, there are 450000 possible different codes</em>

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Computing the <u>ratio of raisins to ounces</u>, it is found that due to the <u>higher computed ratio</u>, brand B advertises the greatest ratio of raisins per ounce.

---------------------------

  • For <em>brand A</em>, there are 60 raisins in the 24-ounces box, thus the ratio is of \frac{60}{24} = 2.5, that is, 2.5 raisins per ounce.
  • For <em>brand B</em>, there are 18 raisins in the 6-ounce box, 36 in the 12-ounce, and it follows this ratio, thus \frac{36}{12} = \frac{18}{6} = 3, thus, 3 raisins per ounce.
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  • Due to the <u>higher computed ratio</u>, brand B advertises the greatest ratio of raisins per ounce.

A similar problem is given at brainly.com/question/24622075

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