Complete Question
The access code for a car's security system consists of 6 digits, the first digit cannot be 8 and the last digit must be odd, how many different codes are available
Answer:
There are 450000 possible different codes
<em></em>
Step-by-step explanation:
Given
Code = 6 digits
First = All but 8
Last = Odd
Required
Determine the possible number of codes
Analyzing each individual digit that makes up the code.
First: can be any of 0,1,2,3,4,5,6,7,9 ----- 9 possible numbers
Second, Third, Fourth and Fifth can be any of 0,1,2,3,4,5,6,7,8,9 since there's no restriction ----- 10 possible numbers
Last can be any of: 1,3,5,7,9 ----- 5 possible numbers
So, the number of possible selections is:


<em>Hence, there are 450000 possible different codes</em>