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Lesechka [4]
2 years ago
10

The access code for a​ car's security system consists of digits. The first digit cannot be and the last digit must be . How many

different codes are​ available?
Mathematics
1 answer:
Semenov [28]2 years ago
7 0

Complete Question

The access code for a car's security system consists of 6 digits, the first digit cannot be 8 and the last digit must be odd, how many different codes are available

Answer:

There are 450000 possible different codes

<em></em>

Step-by-step explanation:

Given

Code = 6 digits

First = All but 8

Last = Odd

Required

Determine the possible number of codes

Analyzing each individual digit that makes up the code.

First: can be any of 0,1,2,3,4,5,6,7,9 ----- 9 possible numbers

Second, Third, Fourth and Fifth can be any of 0,1,2,3,4,5,6,7,8,9 since there's no restriction ----- 10 possible numbers

Last can be any of: 1,3,5,7,9 ----- 5 possible numbers

So, the number of possible selections is:

Selection = 9 * 10 * 10 * 10 * 10 *5

Selection = 450000

<em>Hence, there are 450000 possible different codes</em>

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Six times a number is 45 greater than the the product of the number and -3. Find the number.
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Let us try to formulate the expressions one by one.

let the number be x.

Step 1:

six time the number is 6*x = 6x

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now let us make equation for it:

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adding 3x on the left side,

6x+3x = 45

9x = 45

dividing right side by 9

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