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4 years ago

4. How do you graph the point (5, 2) on the coordinate plane?

Mathematics

2 answers:

Ira Lisetskai [31]4 years ago

7 0

Answer:

A. Plot a point that is 5 units rightward and 2 units up from the origin.

Step-by-step explanation:

NARA [144]4 years ago

6 0

Answer:

4.:C 5: POSSIBLY B 6: Couldn't tell ya my G because i can't see the graph but I did my best.

Step-by-step explanation:

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There are 6 students. 2 of them are chosen for the position of president and Vice President. How many ways do we have to choose

Nutka1998 [239]

We have 15 ways to chose 2 students for the position of president and Vice President

Solution:

Given that,

There are 6 students. 2 of them are chosen for the position of president and Vice President.

To find: number of ways we have to choose the students from the 6 students

So now we have 6 students, out of which we have to choose 2 students

As we just have to select the students. We can use combinations here.

In combinations, to pick "r" items from "n" items, there will be $^{\mathrm{n}} \mathrm{C}_{\mathrm{r}}$ ways

$^{\mathrm{n}} \mathrm{C}_{\mathrm{r}}=\frac{n !}{(n-r) ! r !}$

Then, here we have to pick 2 out of 6:

Total students = n = 6

students to be selected = r = 2

$\begin{aligned} 6 C_{2} &=\frac{6 !}{(6-2) ! 2 !} \\\\ 6 C_{2} &=\frac{6 !}{4 ! 2 !} \\\\ 6 C_{2} &=\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1 \times 2 \times 1} \\\\ 6 C_{2} &=15 \end{aligned}$

Thus we have 15 ways to chose 2 students for the position of president and Vice President

3 0

3 years ago

How many positive integers less than 100 have at least one digit that is a 9? (Let T be the set of positive integers less than 1

Ymorist [56]

Answer:

Step-by-step explanation:

Let T be the set of positive integers less than 100 with a 9 in the ten's place.

T = {90, 91, 92, 93, 94, 95, 96, 97, 98, 99}

n(T) = 10

Let O be the set of positive integers less than 100 with a 9 in the one's place.

O = {9, 19, 29, 39, 49, 59, 69, 79, 89, 99}

n(O) = 10

The common element is 99.

$T\cap O={99}$

$n(T\cap O)=1$

The union of both sets is

$n(T\cup O)=n(T)+n(O)+n(T\cap O)$

$n(T\cup O)=10+10-1$

$n(T\cup O)=19$

Therefore, 19 positive integers are less than 100 those have at least one 9.

6 0

3 years ago

Rachel's free throw average for basketball is 60%. She wants to predict how many times in the next 50 tries she will make a free

sattari [20]

She divided them both

8 0

3 years ago

If 2 - 2 is a factor of 2.? - bx - 10, what is the value of b?

aleksandr82 [10.1K]

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3 years ago

I have to turn this in tonight please help :(

Leni [432]

Answer:

angle a is 116 degrees

Step-by-step explanation:

ok so first we have to make everything equal to 180 because every triangle is 180 degrees so it would be written like this:

(14x + 4) + (5x - 1) + (2x + 9) = 180

Then, we solve for x and x equals 8

After this we plug 8 back into the angle so it would be written like this:

14(8) + 4

This equals 116 degrees.

3 0

3 years ago

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