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2 years ago

In which quadrant is the ordered pair ( 7, -8 ) located? *

Mathematics

2 answers:

Semmy [17]2 years ago

6 0

The ordered pair is located in Quadrant IV

Paul [167]2 years ago

4 0

Answer:

i think IV

Step-by-step explanation:

because of the picture

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If f(x)=4x^3 - 6x^2 + 2x - 5, then f(-2) = ___________

Art [367]

f(x)=4x^3 - 6x^2 + 2x - 5

f(-2)

Replace X with -2:

4(-2)^3 - 6(-2)^2 + 2(-2) - 5 =

Calulate the powers:

4(-8) - 6(4) +(-4) -5=

Multiply:

-32 - 24 -4 -5=

Subtract

-65

7 0

3 years ago

The equation R=10a-20 represents the revenue R (in dollars) you make by spending A dollars on advertising. You revenue totaled $

timurjin [86]

R = 10a - 20
ur revenue totaled 110...so R = 110

110 = 10a - 20
110 + 20 = 10a
130 = 10a
130/10 = a
13 = a <== so u spent $13 on advertising

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2 years ago

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What is the median of the data displayed in this box-and-whisker plot? A.41 B.49 C.55 D.58

lutik1710 [3]

The median in a whisker plot is the dot or line in the box on the line. In this case, the dot is at 41, so the median is 41.

ANSWER: A) 41 is the median

Hope this helps! :)

7 0

3 years ago

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Solve for a,b 2^a × 2^b=144 value of a+3b+2 is...<br><br>please solve it...urgent...

Nadya [2.5K]

Answer:

its a simple for me

Step-by-step explanation:

2+144 i

4 0

2 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

3 0

2 years ago