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3 years ago

How do I solve this question by simplifying?

Mathematics

1 answer:

suter [353]3 years ago

5 0

Answer:

perimeter: 22x-14

area : 24x^2-37x

Step-by-step explanation:

for perimeter, it is the length of all the sides added together

starting at the left and working clockwise

5x+((6x-7)-(3x+1))+2x+(3x+1)+(5x-2x)+(6x-7)

5x+6x-7-3x-1+2x+3x+1+5x-2x+6x-7

combine like terms

perimeter: 22x-14

for area, area of (5x*(6x-7)) and subrtact the missing portion of (2x*(3x+1))

(30x^2-35x)-(6x^2+2x)

area : 24x^2-37x

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Find the value of c so that the polynomial p(x) is divisible by (x-3). p(x) =-x^3+cx^2-4x+3. c=?

Vilka [71]

Answer:

$\boxed{\textsf {The value of c is $\sf \dfrac{-14}{3}$. }}$

Step-by-step explanation:

A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,

$\sf \implies p(x)=- x^3+cx^2-4x+3$

And the factor is ,

$\sf \implies g(x) = x + 3$

Now , according to factor theorem , p(x) will be divisible by g(x) if p(-3) = 0

$\sf \implies p(x)= - x^3+cx^2-4x+3 \\\\\implies\sf p(-3) = 0 \\\\\sf\implies -(-3)^3+c(-3)^2-4(-3)+3 = 0 \\\\\sf\implies 27 + 9c +12+3=0 \\\\\sf\implies 9c +42=0 \\\\\sf\implies 9c = (-42) \\\\\sf\implies c = \dfrac{-42}{9}\\\\\sf\implies \boxed{\pink{\sf c = \dfrac{-14}{3}}}$

<h3>Hence the value of c is (-14)/3 .</h3>

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3 years ago

Jose has 4 friends and 3 apples how much would each friend get if he shared

blsea [12.9K]

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4 years ago

Read 2 more answers

? Don't Send links, don't Write random things and get the points for free.

alekssr [168]

Answer:

$V = 1847.26\ ft^3$

Step-by-step explanation:

Step 1: Determine the volume

$V=\pi r^2h$

$V = \pi *(7\ ft)^2 * (12\ ft)$

$V = \pi *49\ ft^2 * 12\ ft$

$V = \pi * 588\ ft^3$

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Answer: $V = 1847.26\ ft^3$

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2 years ago

Order the following numbers in Ascending order: 2/3, 1/5, 4/5, 1/3

a_sh-v [17]

Answer:

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3 years ago

Read 2 more answers

prove the following identity: sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x please provide a proof in some shape form or fash

wolverine [178]

Answer:

Step-by-step explanation:

Hello,

Is this equality true ?

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

1. let 's estimate the left part of the equation

$sec(x)csc(x)(tan(x) + cot(x)) =\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin(x)}{cos(x)}+\dfrac{cos(x)}{sin(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{sin^2(x)+cos^2(x)}{sin(x)cos(x)})\\\\=\dfrac{1}{cos(x)sin(x)}*(\dfrac{1}{sin(x)cos(x)})\\\\\\=\dfrac{1}{cos^2(x)sin^2(x)}$

1. let 's estimate the right part of the equation

$2+tan^2(x) + cot^2(x)=2+\dfrac{sin^2(x)}{cos^2(x)}+\dfrac{cos^2(x)}{sin^2(x)}\\\\=\dfrac{2cos^2(x)sin^2(x)+cos^4(x)+sin^4(x)}{cos^2(x)sin^2(x)}\\\\=\dfrac{(cos^2(x)+sin^2(x))^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1^2}{cos^2(x)sin^2(x)}\\\\=\dfrac{1}{cos^2(x)sin^2(x)}$

This is the same expression

sec x csc x(tan x + cot x) = 2+tan^2 x + cot^2 x

hope this helps

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3 years ago