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3 years ago

What is the factorization of x^2-6x+5

Mathematics

1 answer:

zimovet [89]3 years ago

5 0

The answer is (x-5) (x-1)

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Karen deposited $5,000 as a certificate of deposit (CD) in a bank for a period of 3 years. The CD pays simple interest of 15% pe

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375 every 6 months ..........

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3 years ago

Help me this is due tomorrow

Tresset [83]

Answer:

10.50

Step-by-step explanation:

in total she would have spent 10.50 because 8.75 for the peaches and 1.75 for the ice cream sandwich

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2 years ago

A school bus weighs 15{,}59115,59115, comma, 591 kilograms.

BabaBlast [244]

Answer:

why should anyone care about a school bus

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2 years ago

–34 = –2(g − 70) g = _____

olganol [36]

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▹ Answer

g = 87

▹ Step-by-Step Explanation

-34 = -2(g - 70)

Divide both sides

17 = g - 70

Rearrange the terms

-g + 17 = 70

Calculate

-g = -87

Change the signs

g = 87

Final Answer

g = 87

Hope this helps!

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7 0

3 years ago

Read 2 more answers

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

4 0

3 years ago