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bagirrra123 [75]
4 years ago
5

From left to right, complete the table of values for the function y - 4 = -3(x + 2).

Mathematics
1 answer:
USPshnik [31]4 years ago
5 0

Answer:

4-5 3

Step-by-step explanation:

because im smart

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A certain fish grows so that after t years of life its length is given by L(t) = 9 − 1/5t inches. Calculate the average rate of
vfiekz [6]

Answer:

Step-by-step explanation:

Given the length of a fish after t years modeled by the equation

L(t) = 9 − 1/5t

The average rate of growth is expressed as;

dL/dt = -1/5 (differential of a constant is zero)

Hence the average rate of growth  over the first year of life is -1/5 in/year

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%5Csqrt%7B20%7D%20-%202%5Csqrt%7B45%7D%20%2B%5Csqrt%7B5%7D%20%29%2A%5Csqrt%7B5%7D" id="TexF
nataly862011 [7]

Answer:

<h2><em><u>-15</u></em></h2>

Step-by-step explanation:

(\sqrt{20} - 2\sqrt{45} +\sqrt{5} )*\sqrt{5}

=  \sqrt{20}  \times  \sqrt{5}  - 2 \sqrt{45}  \times  \sqrt{5}  +  \sqrt{5}  \times  \sqrt{5}

=  \sqrt{100}  - 2 \sqrt{225}  +  \sqrt{25}

= 10 - 2 × 15 + 5

= 10 - 30 + 5

= 15 - 30

=<em><u> -15 (Ans)</u></em>

7 0
3 years ago
/10
Dmitry [639]

Answer:

The average rate will be -11000 dollars per year.

Step-by-step explanation:

The price of a house in 2005 = $250,000

The  price of a house in 2010 = $195,000

at x₁ = 2005, f(x₁) = 250,000

at x₂ = 2010,  f(x₂) = 195,000

Using the formula to determine the average rate of change for the

house each year.

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                      = [195,000 - 250,000 ] / [2010-2005]

                      = -55000 / 5

                      = -11000

Therefore, the average rate will be -11000 dollars per year.

3 0
4 years ago
Based on the following calculator output, determine the inter-quartile range of the dataset.
sergeinik [125]
The whole thing Is confusing
3 0
3 years ago
In the warmer months, Ms.Selwa likes to run to school to get in her daily exercise. She can run 1/6 of a kilometer in a minute.
Lerok [7]

Answer:

3 minutes

Step-by-step explanation:

If Ms. Selwa can run 1/6 of a kilometer in a minute, she can run 3/6 of a kilometer in 3 minutes.

This is because 1/6 times 3 equals 3/6, which is the distance of the school from her home.

So, it will take Ms. Selwa 3 minutes to run to school.

8 0
3 years ago
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