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andrew-mc [135]
3 years ago
14

blog bam shroom im boreddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddboreddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddboreddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddboredddddddddddddddddddddddddddddddddddddddddd
Mathematics
2 answers:
MrRissso [65]3 years ago
8 0
Hahahahahahahahaah ok
kogti [31]3 years ago
5 0
BOOOOOOOOOOOOOOOOOOO
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AlexFokin [52]

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Step-by-step explanation:

3 0
3 years ago
6*1+5*1/10 in standard form
amm1812

Answer:

6.5

Step-by-step explanation:

6 times 1 is 6

5 times 1/10 is 0.5

6+0.5 is 6.5

4 0
4 years ago
Ƒ(x) = 3 - 2x<br><br> (-2, -1)<br> (1, 0)<br> (2, -1)<br> (0, 3)<br> (-1, 5)
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3 0
3 years ago
Which does not represent an equivalent expression to 8x +4
sineoko [7]

Answer:

d) 2x(4x + 2)

Step-by-step explanation:

a) 4(2x + 1) = 8x + 4

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4 0
2 years ago
SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi
Veronika [31]

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

x=48\times 2=96 mi

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Distance=Time\times speed

Distance traveled by other car

y=20\times 2=40 mi

Let z be the distance between two cars after 2 hours later

z=\sqrt{x^2+y^2}

Substitute the values

z=\sqrt{(96)^2+(40)^2}

z=104 mi

Now,

z^2=x^2+y^2

Differentiate w.r.t t

2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}

z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}

Substitute the values

104\frac{dz}{dt}=96\times 48+40\times 20

\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}

\frac{dz}{dt}=52mi/h

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

3 0
3 years ago
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