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tester [92]
3 years ago
11

((x-y)^(2))/(2xy+6y)*(4x+12)/(x^(2)-y^(2)) then it asks "if:"

Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer:

\frac{ {(x - y)}^{2} }{2xy + 6y}  \times  \frac{4x + 12}{ {x}^{2}  -  {y}^{2} }  \\  \frac{(x - y)(x - y)}{2y(x + 3)}  \times  \frac{4(x + 3)}{(x - y)(x + y)}  \\  \frac{(x  - y)}{y}  \times  \frac{2}{(x  +  y)}  \\  \frac{2(x - y)}{y(x + y)}  \\  \frac{(2x - 2y)}{(xy +  {y}^{2}) }

<h2>(2x-2y)/(xy+y^2) is the right answer.</h2>
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Answer this maths question: x³+y³+z³
True [87]

Answer:

(x+y+z)^3

Step-by-step explanation:

5 0
3 years ago
Given the following sets.
Lerok [7]

Answer:

A n C={0,2}

Step-by-step explanation:

From the question,

A={0,1,2,3}

B={a,b,c,d}

C={0,a,2,b}

A n C means A intersection C; and by definition all the members that are common to both set A and C

Hence A n C={0,2}

8 0
3 years ago
Solve the following quadratic equation using the quadratic formula.<br><br> −2y^2+5=7y
Vikki [24]

Answer:

y=(7±√89)/-4

Step-by-step explanation:

y=(-b±√b^2 -4ac)/2a

Rewrite given equation in quadratic form so it is -2y-7y+5=0

Then, in formula, sub -2 for a, -7 for b, and 5 for c

y=-(-7)±√(-7)^2 -4(-2)(5)/2(-2)

When you multiply that out you get

7±√49-(-40)/-4

The next step is the answer given above

If you need the answer not in sq rt form, it is y=-4.1085 and y=0.0608

3 0
3 years ago
Mr. Foster is starting a new job. His salary for the first year is $30,000. He will receive a 5% raise each year after that. Wri
stira [4]

Answer:

s= 30000+1500x

Step-by-step explanation:

Given data

Le the number of years be x

His salary for the first year is $30,000

5% of $30,000

=5/100*30000

= 0.05*30000

= $1500

Hence for x years the salary can be described as

s= 30000+1500x

6 0
3 years ago
The weather was a youth soccer field must be at least 45 m but it cannot exceed 60 m right to inequalities that describe the wid
ss7ja [257]

Answer:

The width of the two soccer field must be given by 45\leq w\leq 60.

Assuming two Integers that are solutions of both inequalities are 45 and 60.

Step-by-step explanation:

Let the width of the youth soccer field be 'w'.

Now Given:

the width of the youth soccer field must be at least 45 m.

So we can say that;

w\geq 45 \ m

Also Given:

the width of the youth soccer field must not exceed 60 m.

So we can say that;

x\leq 60

Hence the width of the two soccer field must be given by 45\leq w\leq 60.

So we can say that;

Any Integer lying between integers 45 and 60 can be considered as the width of the youth soccer field.

So let us Assume two Integers that are solutions of both inequalities are 45 and 60.

7 0
4 years ago
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