Answer:
1. A man Is expected to lead a life of dignity.
2. The tired students went back home after a long day of revelry.
3.An acknowledged expert was invited to tour our campus.
4. The woman was blessed by health and good fortune.
Using the performance planner on a monthly basis allows one to optimize two aspects of an account, which are bid and budget.
<h3>What is a performance planner?</h3>
The performance planner is a tool which helps to obtain the best bids and mean monthly budget around all the campaigns.
The objective of a performance planner are:
- Enhance the conversation number to achieve any upcoming spend premise.
- Helps to obtain the best bids and mean monthly budget.
- Provide the chance to get the benefit of seasonality opportunities.
- Provides new possibilities to enhance the sales through ad and campaigns.
Hence, using the performance planner on a monthly basis allows one to optimize two aspects of an account, which are bid and budget.
Learn more about the performance planner here;
brainly.com/question/14521985
#SPJ1
Answer:
Their is no answer choices but Nonrenewable energy resources include coal, natural gas, oil, and nuclear energy.
Explanation:
Using the information given and the z-distribution, it is found that:
a) The point estimate of the population proportion is 0.5544.
b) The margin of error is: 0.0320.
c) The interval is: (0.5224, 0.5864).
d) The interpretation of the interval is: we are 95% sure that the true population proportion is between 0.5224 and 0.5864.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions has the bounds given by the rule presented as follows:
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which the variables used to calculated these bounds are listed as follows:
is the point estimate of the population proportion.
The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
From the sample, the sample size and the point estimate are given as follows:
![n = 929, \pi = \frac{515}{929} = 0.5544](https://tex.z-dn.net/?f=n%20%3D%20929%2C%20%5Cpi%20%3D%20%5Cfrac%7B515%7D%7B929%7D%20%3D%200.5544)
The margin of error is given by:
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
![M = 1.96\sqrt{\frac{0.5544(0.4456)}{929}}](https://tex.z-dn.net/?f=M%20%3D%201.96%5Csqrt%7B%5Cfrac%7B0.5544%280.4456%29%7D%7B929%7D%7D)
M = 0.0320.
The interval is the point estimate plus/minus the margin of error, hence:
- Lower bound: 0.5544 - 0.0320 = 0.5224.
- Upper bound: 0.5544 + 0.0320 = 0.5864.
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1